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The general equation of a horizontal ellipse is
(x-h)2/a2 + (y-k)2/b2 = 1, at center (h,k) while a = semi-major axis, b = semi-minor axis. These are related through the distance of the focus from the center,c. a2 = b2 + c2.
If you draw the points on a coordinate plane, the center of the ellipse is at (0,0), so h and k equals 0. Then, the minor axis (2b) spans from 8 to -8 of the y-axis. This is equal to 16 units. Hence,
2b = 16
b = 8
b^2 = 64
The distance between the two foci is 2c. Thus,
2c = 12
c = 6
c^2 = 36
Then, a2 = 64 + 36 = 100. Substituting to the general equation:
x^2/100 + y^2/64 = 1
X=2y
2x+5y=9
substitute the x=2y into the second equation
2(2y)+5y=9
multiple the 2y by 2. 4y+5y=9
combine like terms. 9y=9
divide the 9 out from both sides. y=1
plug the y back into the first equation
x=2(1)
multiply. x=2
your answer is: x=2
y=1
Answer: see proof below
<u>Step-by-step explanation:</u>
Use the following Identities:
sec Ф = 1/cos Ф
cos² Ф + sin² Ф = 1
<u>Proof LHS → RHS</u>
