If a quadrilateral is inscribed in a circle then opposite angles are:.

Mathematics

1 answer:

-Dominant- [34]2 years ago

4 0

Answer:

Step-by-step explanation:

Theorem

An inscribed quadrilateral is one where all four angles touch the circumference of the circle containing those 4 angles.

The opposite angles can be shown to be supplementary (that is equal to 180 degrees)

Answer: Supplementary

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The measure of the vertex angle of an isoceles triangle is one- fourth that of a base angle

horsena [70]

Answer:

Base angle = 72

Vertex angle = 18

Step-by-step explanation:

Measure of the base angle = x. But there are two of them. (Definition of isosceles). Keep that in mind.

The vertex angle is 1/4 of one of the base angles. That means that the vertex is 1/4 x

All three angles = 180 degrees.

So we have x + x + x/4 = 180 degrees.

change 1/4x to 0.25x x since 1/4 = 0.25

Equation

x + x + 0.25 = 180

2.5x = 180

Solution

2.5x = 180 Divide by 2.5 on both sides

2.5x/2.5 = 180/2.5

x = 72

Answer

That means that each base angle = 72 degrees

The Vertex Angle = 72/4 = 18

8 0

3 years ago

Please help me find limit

cluponka [151]

9514 1404 393

Answer:

-13/11

Step-by-step explanation:

Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...

$\displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}$