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podryga [215]
3 years ago
8

Almost done pls help

Mathematics
1 answer:
Schach [20]3 years ago
8 0

Answer:

No

Step-by-step explanation:

Because, the radius on AI is 2" while LD is 3".

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A feature film runs 2 h 12 min. The theater requires 12 min between performances, and has 12 min of previews and short subjects
GenaCL600 [577]

1:00 ? because it <em>says </em>that there is a needed 12 minuted between the films plus another 12 minutes of previews which equals 24.... sooo 24 plus 36 should equal 60 which is an hour so the answer as far as i know is 1:00.... Hope this helped :)

4 0
4 years ago
help please i been stuck for 2 hours........... the triangle above is a right-angled isosceles triangle. what would the measurem
Likurg_2 [28]

Answer:

4√2 or 5.66

Step-by-step explanation:

x² + x² = 8²

=> 2x² = 64

=> x² = 32

=> x = √32 = 4√2 or 5.66

8 0
3 years ago
A small refrigerator is a cube with a side length of 16 inches. Use the formula S = 6s2 to find the surface area of the cube.
PilotLPTM [1.2K]
6*16^2=1536 in
A=1536 in
The surface area of the cube is 1536 in.
5 0
3 years ago
Read 2 more answers
Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
Can someone help me asap !!
aivan3 [116]

Answer:

The answer is negative. Answer choice B

Step-by-step explanation:

Here is the question:

-3^40(5.6/2.1)

According to order of operations, we must do -3^40 first.

Its important to note that -3^40 is different than (-3)^40. In the problem you specified, the ^40 only applies to the 3, not -3. So, first we do 3^40 which is a huge number. And then, we need to add a negative symbol to that huge number. So now we have a massive negative number multiplied by 5.6/2.1, which is obviously positive. Obviously, a negative number multiplied by a positive number is still negative. Therfore, the answer is negative.

I hope my answer helped you :)

If you are happy with my answer please vote Brainliest. Thanks!

8 0
2 years ago
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