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Anna71 [15]
3 years ago
10

To the nearest tenth of a mile how many miles from the runway is the airplane at the start of this approach the figure is not dr

awn to scale
Mathematics
1 answer:
nikklg [1K]3 years ago
4 0
Hey guys im gonna be really nice, ima give you the answers for connexus <span>Geometry Semester B: 1) D 2) B 3) A 4) D 5) B 6) C 7) D 8) A 9) A 10) NO 11) OBTUSE 12) C 13) A 14) D 15) B 16) A 17) LAST GRAPH 18) D 19) A 20) B 21) B 22) B 23) C 24) A 25) B 26) A 27) A 28) B 29) B 30) B 31) A 32) A 33) B 34) B 35) B 36) D 37) A 38) A 39) A 40) B 41) D 42) A 43) B 44) A 45) B 46) D 47) C 48) A 49) D 50) D 
These r 100% correct i promise if ur in connexus you will get all correct! hope this helps you guys out :3</span>
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What is 10√273s · 3√14st³u³
tensa zangetsu [6.8K]

Answer:

its 210stu\sqrt{78tu}

6 0
3 years ago
Solve for x and round yout answer to the nearest tenth.
Evgesh-ka [11]

Answer:

x=21.35764429=21.4

Step-by-step explanation:

Take SOHCAHTOA

in this problem you're going to use SOH, which is sine= opposite/hypotenuse

sin31=11/x

Multiply by x as a way to isolate it

x(sin31)=11

divide my sin31 to isolate x

x=11/sin31

x=21.35764429

5 0
3 years ago
sex(-x)-sin(-x)tan(-x)=cosx Note that each Statement must be based on a Rule chosen from the Rule menu. To see a detailed descri
julsineya [31]

Answer:

Step-by-step explanation:

sec (-x)-sin (-x) tan (-x)=cos x

sec(x)-(-sin x)(-tan x)=cos x

1/cos x-sin x(sin x/cos x)=cos x

multiply by cos x

1-sin ²x=cos²x

or 1=sin²x+cos²x

which is true.

4 0
3 years ago
On Novermber 27, 1993, the New York times reported that wildlife biologists have found a direct ink between the increase in the
Korolek [52]

Answer:

a.  1 263 888

b. 130 701

c. 72 years

Step-by-step explanation:

a. The differential equation applies here.

Let the quantity increase for a certain time be given by Q(t)

Every unity of time, the quantity increases by 1+\frac{r}{100} so that after the time t, the quantity remaining will be given by:

Q(t) = (1+ \frac{r}{100} )^{t}

In a similar manner, the quantity R(t) decreases at a rate given by the following expression:

1-\frac{r}{100} and after the time , t the quantity of R remaining will be given by:

R(t) = (1-\frac{r}{100} )^{t}

a. To find the population of humans in 1953

Q(t) = (1+ \frac{r}{100} )^{t}

1993 - 1953 = 40 years = t

Q(40) = Q×1.06^{40}

Q = 1 263 888.44

    ≈ 1 263 888

b. For bear population in 1993:

R(t) = (1-\frac{r}{100} )^{t}

t = 40

R(40) = b 0.94^{40} = 11 000

b = 130 700. 889

    ≈130 701

c. time taken for black bear population number less than 100 is given by:

130 = 11000×0.94^{t}

solving using natural logarithms gives t = 72.72666

                                                                  =   72 years Ans

8 0
3 years ago
Please help. Subject is Pythagorean theorem
pashok25 [27]
3 because I said so and it is correct
8 0
3 years ago
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