Answer:
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
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I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
Answer:
Step-by-step explanation:
1) Given figure is a parallelogram
Area = 144 cm²
base * altitude = 144
16 * x = 144
x =144/16
x = 9 cm
2)2) Trapezium
Area = 
; {a and b are parallel sides of trapezium}
( 37 +27 /2) * x = 480 cm²
64/2 * h = 480
32 * h = 480
h = 480/32
h = 15 cm
Answer:
D
Step-by-step explanation:
D. 2(5) > 7
10 > 7
Answer:
3/8
Step-by-step explanation:
they simply combined the like terms (aka the x numbers in this case) so all that's left is 3/8
