No, it is not. I will show you:
-1 = x and 2 = y
2 = -5(-1) + 7
2 is not equal to 12. I hope this is right!
Answer:
Step-by-step explanation:
The null hypothesis is:
H0: μ(1995)=μ(2019)
The alternative hypothesis is:
H1: μ(1995)<μ(2019)
Because Roger wants to know if mean weight of 16-old males in 2019 is more than the mean weight of 16-old males in 1995 the test only uses one tail of the z-distribution. It is not a two-sided test because in that case the alternative hypothesis would be: μ(1995)≠μ(2019).
To know the p-value, we use the z-statistic, in this case 1.89 and the significance level. Because the problem does not specify it, we will search for the p-value at a 5% significance level and at a 1%.
For a z of 1.89 and 5% significance level, the p-value is: 0.9744
For a z of 1.89 and 1% significance level, the p-value is: 0.9719
18×30%=
18×.30=5.4
5.4 is the amount of clearanceyou get from the item
Know you have to subtract $5.40 from $18.00
18-5.4=12.6
The item is know $12.60
Obtuse angle. If wrong I’m sorry lol
Easy peasy
just use PEMDAS and some exonential laws
also another is
![x^{\frac{m}{n}}=\sqrt[n]{x^{m}}](https://tex.z-dn.net/?f=%20x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%7D%20)
so
![[3(2a)^{\frac{3}{2}}]^{2}](https://tex.z-dn.net/?f=%20%5B3%282a%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%5D%5E%7B2%7D%20)
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