Answer:
-¹²/₅
Step-by-step explanation:
Let cos a = -⁵/₁₃
Then tan a = sin a/cos a
= [√(1 - cos²a)]/cos a
= {√[1 - (-⁵/₁₃)²]}/(-⁵/₁₃)
= -[√(1 - ²⁵/₁₆₉)] × ¹³/₅
= -[(√(¹⁴⁴/₁₆₉ )] × ¹³/₅
= -¹²/₁₃ × ¹³/₅
= -¹²/₅
tan(arccos (-⁵/₁₃)) = -¹²/₅
The diagram shows the 2nd quadrant of a circle with radius 13, cos a = -⁵/₁₃, and tan a = ¹²/₍₋₅₎ = -¹²/₅.
Short answer: Yes.
Each member of the sequence is multiplied by 5 to get to the next member of the sequence.
Find the general equation.
tn = a*5^(n - 1)
Example
t4 = 1*5^(4 - 1)
t4 = 1*5^3
t4 = 125 just as the sequence shows.
t5 = 1^5^4
t5 = 625 Any member of the sequence can be found this way.
It’s 15x plus 1 I believe it is the sender
B. 102.57 cu. cm is the answer
Solution:
V=πr^2h
The diameter is 14. To find the radius you divide the radius by 2 which is equal to 7. [Radius is 2 times diameter]
V= 3.14×7×7×2
V= 102.57
