<em>Answer,</em>
<em><u>S = -16</u></em>
<em>Explanation,</em>
<em><u>Step 1: Simplify both sides of the equation.</u></em>
<em>13 + 11s = − 15 + 8s − 20</em>
<em>13 + 11s = − 15 + 8s + − 20</em>
<em>11s + 13 = (8s) + (</em><em><u>− 15</u></em><em> + </em><em><u>− 20</u></em><em>) </em><em>(Combine Like Terms)</em>
<em>11s + 13 = 8s + − 35</em>
<em>11s + 13 = 8s − 35</em>
<em><u>Step 2: Subtract 8s from both sides.</u></em>
<em>11s + 13 − 8s = 8s − 35 − 8s</em>
<em>3s + 13 = − 35</em>
<em>Step 3: Subtract 13 from both sides.</em>
<em>3s + 13 − 13 = − 35 − 13</em>
<em>3s = − 48</em>
<em><u>Step 4: Divide both sides by 3.</u></em>
<em>3s/3 = −48/3</em>
<em>s = -16</em>
<u><em>Hope this helps :-)</em></u>
Answer:
7/2
Step-by-step explanation:
rewrite the equation
7 / 6 / 3
7 /2
simplest doesn't mean answer fully just get to the simplest form where there are only absolute numbers
Answer:
8:55
Step-by-step explanation:
7:30 plus 1 hour is 8:30. Quarter is 25 or 1/4. Then you add 8:30 plus 25 which gives you 8:55.
Yes. If the diagonals bisect the angles, the quadrilateral is always a parallelogram, specifically, a rhombus.
Consider quadrilateral ABCD. If diagonal AC bisects angles A and C, then ΔACB is congruent to ΔACD (ASA). Hence AB=AD and BC=CD (CPCTC).
Likewise, if diagonal BD bisects angles B and D, triangles BDA and BDC are congruent, thus AB=BC and AD=CD. (CPCTC again). Now, we have AB=BC=CD=AD, so the figure is a rhombus, hence a parallelogram.
