All categories

2 years ago

POSSIBLE POINTS: 8

Mathematics

1 answer:

Mamont248 [21]2 years ago

4 0

Answer:

x = 5

Step-by-step explanation:

Jeez this diagram is horribly drawn.

16/32 = 26/(32 + 4x)

16(32 + 4x) = 32(26)

32 + 4x = 2(26)

4x = 20

x = 5

Wow, my incorrect answer happened to also be the actual right one, wooh!

You might be interested in

Whats 6278 divided by 73 long division please show the work

FrozenT [24]

I can't show the work, but if the problem is printed or on the computer, I recommend using Photomath in the AppStore :)

4 0

3 years ago

Read 2 more answers

Find the equation of the line that passes through the pair of points. (-5,3) (-5,0)

sladkih [1.3K]

Answer:

x = -5

Step-by-step explanation:

Note that x does not change. Hence, this line is a vertical one, and its slope is undefined. The line is defined by the equation x = -5.

8 0

3 years ago

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

3 years ago

1/6 of 3 yards=______feet<br><br>I know I just ask one but u get 17 points so plz help I'm stuck

bulgar [2K]

In this question, first we have to see how many feets are in 1 yard .

And there are 3 feets in 1 yard.

So in 3 yards, there are 9 feets

Therefore we will get

$\frac{1}{6}*3 yards= \frac{1}{6} * 9 feet = 1.5 feet$

Therefore the answer of the given question is 1.5 feet.

3 0

3 years ago

How do I solve for g?

chubhunter [2.5K]

Answer:

g=y-m/x

Step-by-step explanation:

You subtract m on both sides then you divide by x

It would look like

g=y-m/x

6 0

2 years ago