Angle A = 3x - 10
Angle B = x
Their angle sum = 90° ( complementary angles form 90° )
This can be written in an equation as =
= 3x - 10 + x = 90
= 3x + × + ( -10 ) = 90
= 4x + (-10) = 90
= 4x = 90 + 10 ( transposing-10 from LHS to RHS changes-10 to +10 )
= 4x = 100
= x = 100 ÷ 4 ( transposing ×4 from LHS to RHS changes ×4 to ÷4 )
= x = 25
Angle A = 3x - 10
= 3 × 25 - 10
= 75 - 10
= Angle A = 65°
Angle B = x = 25°
Their sum = 65 + 25 = 90°
Therefore , the complementary angles , Angle A = 65° and Angle B = 25° .
<h3>
Answer: Choice A) 9 combinations</h3>
Explanation:
Imagine you had a table with 3 rows and 3 columns. The rows represent the possible main dishes (Chicken, Fish, Beef) and the rows represent the side dishes (Rice, Potatoes, Vegetables).
The table has 3*3 = 9 cells inside it. Each inner cell represents a different combo the customer can order.
<span>The probability that a house in an urban area will develop a leak is 55%. if 20 houses are randomly selected, what is the probability that none of the houses will develop a leak? round to the nearest thousandth.
Use binomial distribution, since probability of developing a leak, p=0.55 is assumed constant, and
n=20, x=0
and assuming leaks are developed independently between houses,
P(X=x)
=C(n,0)p^x* (1-p)^(n-x)
=C(20,0)0.55^0 * (0.45^20)
=1*1*0.45^20
=1.159*10^(-7)
=0.000
</span>
Answer:
Each person would receive maximum 0.8 pounds of potato.
Step-by-step explanation:
Given:
Total Amount of Potato = 16 pounds.
Number of people attend reunion = 20
We need to find the largest amount of potato each person would receive.
Solution:
largest amount of potato each person would receive can be calculated by dividing Total Amount of Potato with Number of people attend the reunion.
framing in equation form we get;
largest amount of potato each person would receive = 
Hence Each person would receive maximum 0.8 pounds of potato.
Perimeter simply represents the sum of all side lengths of a shape. The length of the missing side of the ticket is 5 cm; the length of gold line on each ticket is 20 cm, and 2 bottles of gold ink are required to draw gold lines on 200 tickets.
I've added the image of the ticket as an attachment.
(a) The missing side length
From the attachment, the 4 unknown side lengths are equal. Represent this side length with L.
So, we have:

This gives


Collect like terms


Divide both sides by 4

(b) The length of the gold lines
There are 4 slant lines and the length of one of the slant lines is 5 cm (as calculated above).
So, the length of the gold line is:



(c) The number of gold ink bottles.
--- number of tickets
The length of all gold line in the 200 tickets is:



---- convert to meters

Given that:
--- 1 bottle for 20 m
The number of bottles (n) is:



Hence, 2 bottles of gold ink are enough.
Read more about perimeters at:
brainly.com/question/6465134