Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
Answer:
i dont see the figure
Step-by-step explanation:
hjo
Answer:
see explanation
Step-by-step explanation:
(1)
Since FE = FG the triangle is isosceles with ∠ E = ∠ G, then
∠ E =
=
= 37°
(2)
Since all 3 sides are congruent then triangle is equilateral with the 3 angles being congruent, 60° each , then
12y = 60 ( divide both sides by 12 )
y = 5
(3)
The 3 angles are congruent then triangle is equilateral with the 3 sides being congruent, then
KL = JL , that is
4t - 8 = 2t + 1 ( subtract 2t from both sides )
2t - 8 = 1 ( add 8 to both sides )
2t = 9 ( divide both sides by 2 )
t = 4.5
(4)
Given ∠ B = ∠ C then triangle is isosceles with 2 legs being congruent , that is
AB = AC
4x + 1 = 9 ( subtract 1 from both sides )
4x = 8 ( divide both sides by 4 )
x = 2
Then
perimeter = AB + BC + AC = 4x + 1 + 2x + 3 + 9
= 6x + 13
= 6(2) + 13
= 12 + 13
= 25
Divide both the numerator and denominator by the gcf, which is 3.
3/3=1
6/3=2
Final answer: 1/2
Answer:
2/5
Step-by-step explanation:
20 x 3 = 60
2/15 x 3 = 2/5
Sidenote: Hope this helps! :D