answer is -1 < x < 5
-|x - 2|+ 9 > 6
Rearrange the terms
-|x - 2| > 6 - 9
-|x - 2| > - 3
then divide both sides of the inequality by the co- efficient of variable
|x - 2| < 3
convert the absolute inequality to standard inequality
-3 <x - 2 < 3
separate compound inequalities into system of inequality
{x - 2}> -3
{x - 2 < 3}
Rearrange variable to the left side of the equation
x > -3 + 2
calculate the sum or difference
x > -1
x -2 < 3
Rearrange variable to the left side of the equation
x < 3 + 2
calculate the sum or difference
x < 5
x > -1 and x < 5
Find intersection
-1 < x < 5
Equations and inequalities are both mathematical sentences formed by relating two expressions to each other. In an equation, the two expressions are deemed equal which is shown by the symbol =. Where as in an inequality, the two expressions are not necessarily equal which is indicated by the symbols: >, <, ≤ or ≥.
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Answer:
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We have:

Thus:

Adding

gives:

Factoring gives:

Thus, we have:

or

.
Note that because

, there will be no solutions

of the form

for positive integer

and solution

. So we find the basic values of

giving

.
For

with positive

,

(this can be seen easily from the unit circle. But

, a contradiction. So we examine the case in which

.
In this case,

. So this is the only solution to this equation.
Substituting this back in, we have

, as desired. So this is a valid solution.
Thus,

.
Area of the circle is 78.5 sq. units.
<u>Step-by-step explanation:</u>
Circumference of the circle = 31.4 units
2 π r = 31.4 units
2 × 3.14 ×r = 31. 4 units
r = 31.4 / (2×3.14)
= 5 units.
Area of the circle = π r² = 3.14 × 5 × 5 = 78.5 sq. units.
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