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3 years ago

The formula d = rt. Find how long it takes an airplane to fly 375 at 500 miles per hour

Mathematics

1 answer:

8090 [49]3 years ago

8 0

375=500t 375/500=t 0.75=t

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timurjin [86]

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2 years ago

In how many ways can 10 people form couples of two?

maxonik [38]

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It should be 10 raised to power 2 which is a hundred.

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2 years ago

Expand and simplify pla

k0ka [10]

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2 years ago

2X+2Y=48<br> 3X+Y=40 <br><br> What is X and Y

marshall27 [118]

Answer:

x=8

y=16

Step-by-step explanation:

2x+2y=48

3x+y=40

Ther is many ways to solve this, one of them is clearance:

WE CLEAR AN UNLOCKED (X) AND REPLACE IT IN THE OTHER

x= (40-y)/3

2[(40-y)/3] +2y=48

(80-2y)/3 +2y=48

(80-2y+6y)/3=48

80+4y=48(3)

4y=144

y= 144/4

y=16

x=(40-y)/3

x=(40-16)/3

x=24/3

x=8

4 0

3 years ago

Plz guys help i need asap<br> its part b im stuck

aleksklad [387]

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

1st quarter-2
2nd quarter-9
3rd quarter-7
4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

$\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8$

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

$g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4$

Hence, there are 4 more home goals than away goals.

4 0

3 years ago