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3 years ago

PLZ DONT LEAVE IN BLANK I WILL DO ANYTHING!!!!

Mathematics

1 answer:

mafiozo [28]3 years ago

8 0

Answer:

Option 3

Step-by-step explanation:

Options numbered 1 to 4, top to bottom

Plot the scores in increasing order

20, 24, 25, 27, 29, 31, 34

The first and forth options can be eliminated because the whiskers do not cover the upper end of the range correctly. First ignores 34 and last includes 35, which is not in our score list.

The second option incorrectly places the median score at 25

The third option correctly places the median score at 27, the lower quartile at 24, and the upper quartile at 31

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Is 6 cups more or 2 pints ?

nirvana33 [79]

Answer:

6 Cups

Step-by-step explanation:

1 pint is equal to 2 cups

Therefore 2 pints is equal to 4 cups.

You would need 3 pints for it to be equal to 6 cups.

Hope this helps :) If you have any more questions just ask :)

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2 years ago

Fernando has been saving money to buy an e–book reader. A store has just marked down the price of its readers by 40%. Each reade

Igoryamba

200 and 0 cents is the answer

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1 year ago

17.3152 to the nearest hundredth=

mamaluj [8]

Answer:

17.32

Step-by-step explanation:

since there is a 5 in the thousandths, we round the 1 in the hundredths up and get 17.32

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2 years ago

Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1

IceJOKER [234]

Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

<u>Step-by-step explanation:</u>

Here we have , $cosxtanx - 2 cos^2 x=-1$ . Let's solve :

⇒ $cosxtanx - 2 cos^2 x=-1$

⇒ $cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1$

⇒ $sinx = 2 cos^2 x-1$

⇒ $sinx = 2 (1-sin^2x)-1$

⇒ $sinx = 1-2sin^2x$

⇒ $2sin^2x+sinx-1=0$

By quadratic formula :

⇒ $sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}$

⇒ $sinx = \frac{-1 \pm3}{4}$

⇒ $sinx = \frac{1}{2} , sinx =-1$

⇒ $sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}$

⇒ $x=\frac{\pi}{6} , x=\frac{3\pi}{2}$

But at $x=\frac{3\pi}{2}$ we have equation undefined as $cos\frac{3\pi}{2}=0$ . Hence only solution is :

⇒ $x=\frac{\pi}{6}$

Since , $sin(\pi -x)=sinx$

⇒ $x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}$

Now , General Solution is given by :

⇒ $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$

Therefore , Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

3 0

3 years ago

If -5x-y=1 is a true equation, what would be the value of 5(-5x-y)?

Tanzania [10]

Answer:

-25-5x-5y

Step-by-step explanation:

7 0

3 years ago