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2 years ago

Please help me!! ill mark you brainliest. please actually answer all of em.

Mathematics

2 answers:

Lostsunrise [7]2 years ago

5 0

Answer:

1-a

2-a

3-b

Step-by-step explanation:

hope that helps

Dmitriy789 [7]2 years ago

4 0

A
A
B

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Determine whether the relationship is an inverse variation or not. Explain.

Kazeer [188]

The relationship is not an inverse variation because the product xy is not a constant.

<h3>What is Inverse variation?</h3>

Inverse variation is the relationship between two quantities whereby an increase in one quantity cause a decrease in the other quantity.

In this type of variation the product of the two quantities is constant.

Analysis:

if x is one quantity and y is the other,

Mathematically, x = $\frac{k}{y}$

Where, k is a constant,

it means k = xy

from the table, when, x =2, y = 409, xy = 2 x 409 = 818

Also, x = 3, y = 240, xy = 3 x 240 = 720

Therefore, 720 not equal to 818.

In conclusion, The product xy is not a constant, so the relationship is not an inverse variation.

Learn more about Inverse Variation: brainly.com/question/3781606

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1 year ago

9. The area of a circle is 706.97 in2. Find the radius.

Strike441 [17]

Answer:

Step-by-step explanation:

Using the formula

A=πr2

Solving

r=√A/π

r=√706.97/22/7

r≈15.00118

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2 years ago

Quadrilateral ABCD with vertices A(0, 6), B(-3, -6), C(-9, -6), and D(-12, -3): a) dilation with scale factor of 1/3 centered at

Oksanka [162]

a) The points of the new quadrillateral are $A'(x,y) = (0, 2)$ , $B'(x,y) = (-1, -2)$ , $C'(x,y) = \left(-3,-2\right)$ and $D'(x,y) = (-4, -1)$ , respectively.

b) The points of the new quadrillateral are $A'(x,y) = (-5, 5)$ , $B'(x,y) = (-8,-7)$ , $C'(x,y) = (-13, -7)$ and $D'(x,y) = (-17, -4)$ , respectively.

<h3>How to perform transformations with points</h3>

a) A dillation centered at the origin is defined by following operation:

$P'(x,y) = k\cdot P(x,y)$ (1)

Where:

$P(x,y)$ - Original point
$P'(x,y)$ - Dilated point.

If we know that $k = \frac{1}{3}$ , $A(x,y) = (0,6)$ , $B(x,y) = (-3,-6)$ , $C(x,y) = (-9, -6)$ and $D(x,y) = (-12, -3)$ , then the new points of the quadrilateral are:

$A'(x,y) = \frac{1}{3}\cdot (0,6)$

$A'(x,y) = (0, 2)$

$B'(x,y) = \frac{1}{3} \cdot (-3,-6)$

$B'(x,y) = (-1, -2)$

$C'(x,y) = \frac{1}{3}\cdot (-9,-6)$

$C'(x,y) = \left(-3,-2\right)$

$D'(x,y) = \frac{1}{3}\cdot (-12,-3)$

$D'(x,y) = (-4, -1)$

The points of the new quadrillateral are $A'(x,y) = (0, 2)$ , $B'(x,y) = (-1, -2)$ , $C'(x,y) = \left(-3,-2\right)$ and $D'(x,y) = (-4, -1)$ , respectively. $\blacksquare$

b) A translation along a vector is defined by following operation:

$P'(x,y) = P(x,y) +T(x,y)$ (2)

Where $T(x,y)$ is the transformation vector.

If we know that $T(x,y) = (-5,-1)$ , $A(x,y) = (0,6)$ , $B(x,y) = (-3,-6)$ , $C(x,y) = (-9, -6)$ and $D(x,y) = (-12, -3)$ ,

$A'(x,y) = (0,6) + (-5, -1)$

$A'(x,y) = (-5, 5)$

$B'(x,y) = (-3, -6) + (-5, -1)$

$B'(x,y) = (-8,-7)$

$C'(x,y) = (-9, -6) + (-5, -1)$

$C'(x,y) = (-13, -7)$

$D'(x,y) = (-12,-3)+(-5,-1)$

$D'(x,y) = (-17, -4)$

The points of the new quadrillateral are $A'(x,y) = (-5, 5)$ , $B'(x,y) = (-8,-7)$ , $C'(x,y) = (-13, -7)$ and $D'(x,y) = (-17, -4)$ , respectively. $\blacksquare$

To learn more on transformation rules, we kindly invite to check this verified question: brainly.com/question/4801277

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2 years ago

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Dimas [21]

Answer:

The answer is 9.4 times 10 Superscript negative 8, 9.25 times 10 Superscript negative 6, 2.5 times 10 Superscript 3, 7 times 10 Superscript 3

Step-by-step explanation:

The reason is because i kinda just took the course in ingenuity and also i just took the quiz i hope this helps ;)

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2 years ago

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shtirl [24]

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8h + 0.50t

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2 years ago

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