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2 years ago

I need help asap. Math Writing Expressions.

Mathematics

1 answer:

erica [24]2 years ago

3 0

Answer:

6y-3+y

D =7y-3

50C

6÷K

7-x

8p-4p

2g-3

1-7/p

D.(p-7)/p

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Distance formula for (0,1) (3,7)

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2 years ago

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Step-by-step explanation:

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Jameson Middle School gives bottles of water to teachers and students who are going on a field trip. The school orders 500 bottl

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2 years ago

Simplify the expression csc(-x)/1+tan^2x)

Charra [1.4K]

Assuming ya meant $\frac{csc(-x)}{1+tan^2(x)}$

to slimplify, we use a variation of the pythagorean identity and a decomposition into the sin and cos

for the pythaogreaon identity
$cos^2(x)+sin^2(x)=1$
divide both sides by $cos^2(x)$
$1+tan^2(x)=sec^2(x)$ since $\frac{sin(x)}{cos(x)}=tan(x)$
subsitute
$\frac{csc(x)}{sec^2(x)}$

recall that $csc(x)=\frac{1}{cos(x)}$
also that cos(x) is an even function and thus cos(-x)=cos(x)
therfore $csc(-x)=\frac{1}{cos(-x)}=\frac{1}{cos(x)}=csc(x)$
so we get

$\frac{csc(x)}{sec^2(x)}$
decompose them into $\frac{1}{cos(x)}$ and $\frac{1}{sin^2(x)}$ to get $\frac{\frac{1}{cos(x)}}{\frac{1}{sin^2(x)}}$
multiply by $\frac{sin^2(x)}{sin^2(x)}$ to get
$\frac{sin^2(x)}{cos(x)}$
we can furthur simlify to get
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the expression simplifies to tan(x)sin(x)

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2 years ago

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hjlf

The answer is tan64 = 13/x :)

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