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kirill115 [55]
3 years ago
13

School: Practice & Problem Solving

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
7 0

Answer:

60% of the total people surveyed were satisfied with the car.

Step-by-step explanation:

The total number of people surveyed = 2,600

Number of people who owned a certain type of car

said they would buy it again = 1,560

or, the total number of people who were satisfied with that car = 1,560

Now, \textrm{Percentage of satisfied customers}  = \frac{\textrm{Total number of satisfied customer}}{\textrm{Total surveyed customer}}  \times 100

=\frac{2,600}{1,560}  \times 100 = 60

or, the percentage of satisfied customer = 60%

Hence, 60% of the people surveyed were satisfied with the car.

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PtichkaEL [24]
i hope this helps a little bit

5 0
3 years ago
3. There are 124 acorns laying on the ground in your yard, it is predicted that the number of acorns will
Gennadij [26K]

Answer:

507,409

Step-by-step explanation:

if every 5 days the number quadruples (x4), and we want to know how many acorns fall after 30 days, we can divide 30 by 5 so we only have to calculate for the amount of time the take to quadruple.

30 ÷ 5 = 6

so we only have to quadruple the acorns 6 times.

if we start off with 124 acorns, this is what it will look like:

Day 0: 124 acorns

Day 5: 124 x 4 = 496 acorns

Day 10: 496 x 4 = 1984 acorns

Day 15: 1984 x 4 = 7936 acorns

etc... until day 30.

Day 30: 507904 acorns

I hope this was helpful :-)

5 0
3 years ago
The quotient of nine less than 3 times a number and four is 21how to translate into a sentence
dedylja [7]
Hello,

Let's assume n the number searched.

nine less 3 times n is written 9-3n
 
\dfrac{9-3n}{4} =21\\
==\ \textgreater \  9-3n=84\\
==\ \textgreater \  -3n=75\\
==\ \textgreater \  n=-25



8 0
3 years ago
Find x.<br><br> select one :<br> a. 3/4 <br> b. 1/2 <br> c. 2 <br> d. 4
Dimas [21]

check the picture below.

8 0
3 years ago
50 POINTS
mamaluj [8]

Answer:

The answer is below

Step-by-step explanation:

The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds: A linear model with ordered pairs at 0, 60 and 2, 75 and 4, 75 and 6, 40 and 8, 20 and 10, 0 and 12, 0 and 14, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet. Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(s) of the domain is the water balloon's height staying the same? (2 points) Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points) Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds.

Answer:

Part A:

Between 0 and 2 seconds, the height of the balloon increases from 60 feet to 75 feet  at a rate of 7.5 ft/s

Part B:

Between 2 and 4 seconds, the height stays constant at 75 feet.

Part C:

Between 4 and 6 seconds, the height of the balloon decreases from 75 feet to 40 feet at a rate of -17.5 ft/s

Between 6 and 8 seconds, the height of the balloon decreases from 40 feet to 20 feet at a rate of -10 ft/s

Between 8 and 10 seconds, the height of the balloon decreases from 20 feet to 0 feet at a rate of -10 ft/s

Hence it fastest decreasing rate is -17.5 ft/s which is between 4 to 6 seconds.

Part D:

From 10 seconds, the balloon is at the ground (0 feet), it continues to remain at 0 feet even at 16 seconds.

3 0
3 years ago
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