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malfutka [58]
3 years ago
9

Which pair of numbers is relatively prime

Mathematics
2 answers:
nydimaria [60]3 years ago
6 0

Answer:

D is correct.

Step-by-step explanation:

I just finished taking the quiz.

Anna007 [38]3 years ago
5 0
Without any calculations it's evident it can't be neither B (both numbers are even, so they're divisible by 2) nor C (the numbers end in 0 and 5, so they're divisible by 5).

A.
57=3\cdot19\\
96=2^5\cdot3
Both numbers have a factor of 3, so they're not relatively prime.
That means it must be D. But, let's check it.

143=11\cdot13\\
323=17\cdot19

Indeed, those two numbers are relatively prime.

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Y = -3x + 11<br> y = -6x - 13
Marysya12 [62]

Answer:

x= -8 and so y=35.....solving equation

5 0
3 years ago
ABCD is a rhombus in which angle BAD = 68°
olchik [2.2K]

Answer:

21 69 34

Step-by-step explanation:

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8 0
3 years ago
It took James 5h to paint an 8ft by 24ft wall. At this rate, how long would it take him to paint a 12ft by 36ft wall
olasank [31]
8 * 24 feet = 192 sq feet per 5 hours

12* 36 = 432 square feet

432 is 2.25 times the area of 192 square feet

So, it takes 5 * 2.25 = 11.25 hours


7 0
3 years ago
Find an equation of the sphere that passes through the origin and whose center is (-2, 2, 3). Be sure that your formula is monic
Andrei [34K]

Answer:

\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}

Step-by-step explanation:

Given the center of sphere is: (-2, 2, 3)

Passes through the origin i.e. (0, 0, 0)

To find:

The equation of the sphere ?

Solution:

First of all, let us have a look at the equation of a sphere:

(x-a)^2+(y-b)^2+(z-c)^2=r^2

Where (x,y,z) are the points on sphere.

(a, b, c) is the center of the sphere and

r is the radius of the sphere.

Radius of the sphere is nothing but the distance between any point on the sphere and the center.

We are given both the points, so we can use distance formula to find the radius of the given sphere:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}

Here,

x_1 =0 \\y_1 =0 \\z_1 =0 \\x_2 =-2 \\y_2  =2 \\z_2 =3

So, Radius is:

r = \sqrt{(-2-0)^2+(2-0)^2+(3-0)^2}\\\Rightarrow r = \sqrt{4+4+9} = \sqrt{17}

Therefore the equation of the sphere is:

(x-(-2))^2+(y-2)^2+(z-2)^2=(\sqrt{17})^2\\\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}

4 0
3 years ago
Solve for x: 4(x+6) = 2-6 (x+3)
laiz [17]

Answer:

x = - 4

Step-by-step explanation:

6 0
3 years ago
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