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siniylev [52]
3 years ago
5

(x^2+3y-3) - (-2x^2+3y-1)

Mathematics
1 answer:
Vitek1552 [10]3 years ago
5 0
(x^2+3y-3) - (-2x^2+3y-1)
Apply plus/minus rule.
-(-a)=a amd -(a)=-a
(x^2+3y-3) - (-2x^2+3y-1)=x^2+3y-3+2x^2-3y+1

=x^2+3y-3+2x^2-3y+1 \\
Add \ like \ terms \\
=3x^2 - 2 \\
Answer: \  3x^2-2
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