Question

(x^2+3y-3) - (-2x^2+3y-1)

Answer 1

$(x^2+3y-3) - (-2x^2+3y-1)$
Apply plus/minus rule.
-(-a)=a amd -(a)=-a
$(x^2+3y-3) - (-2x^2+3y-1)=x^2+3y-3+2x^2-3y+1$
$=x^2+3y-3+2x^2-3y+1 \\ Add \ like \ terms \\ =3x^2 - 2$
$Answer: \ 3x^2-2$