2 years ago

(x^2+3y-3) - (-2x^2+3y-1)

1 answer:

5 0

$(x^2+3y-3) - (-2x^2+3y-1)$
Apply plus/minus rule.
-(-a)=a amd -(a)=-a
$(x^2+3y-3) - (-2x^2+3y-1)=x^2+3y-3+2x^2-3y+1
$
$=x^2+3y-3+2x^2-3y+1 \\
Add \ like \ terms \\
=3x^2 - 2 \\$
$Answer: \ 3x^2-2$

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