Question

Please help, I dont know how to do this​

Answer 1

Answer:

$\frac{y-2}{4}$

Step-by-step explanation:

Let's start by factoring everything:

$\dfrac{\frac{y^2+y}{y^2-2y}}{\frac{4y+4}{y^2-4y+4}}=$

$\dfrac{\frac{y(y+1)}{y(y-2)}}{\frac{4(y+1)}{(y-2)^2}}=$

Now, you can cancel out some terms:

$\dfrac{\frac{y+1}{y-2}}{\frac{4(y+1)}{(y-2)^2}}=$

Now, when you divide a fraction by another fraction, that is the same as multiplying the first fraction by the reciprocal of the second one:

$\frac{y+1}{y-2}\cdot \frac{(y-2)^2)}{4(y+1)}=$

$\frac{y-2}{4}$

Hope this helps!