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3 years ago

The cost of 6 CDs are $12, $13, $20, $20, $12.50 and $18.50. What is the mean

Mathematics

2 answers:

Komok [63]3 years ago

6 0

The mean is 16 :))) yw

motikmotik3 years ago

4 0

Answer:

$16

Step-by-step explanation:

Find the mean by adding all of the costs, and dividing it by 6, since there are 6 CDs

(12 + 13 + 20 + 20 + 12.5 + 18.5) / 6

96 / 6

= 16

So, the mean is $16

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Explain, in writing, what each parameter in the given function has on the graph of its parent function. (4 Points) () = −cos(1/2

Andrew [12]

Answer:

The parameters in the parent function are:

the parameter correspondig to - 3 in the given function is 0 in the parent function.
the parameter corresponding to 1/2 in the given function is 1 in the parent function, and
the parameter corresponding to - 1 in the given function is 1 in the parent function.

Explanation:

The given function is $f(x)=-cos(x/2)-3$ .

The parent function of $f(x)=-cos(x/2-3)\text{ }is\text{ }h(x)=cosx$ . The parameters of the given function are -1 (which is mutlyplying the value of cosine, 1/2 which is multiplying the argument (x), and - 3 which is subtracted.

In the parent function, those values are 1, 1, and 0.

It may help you representing the parameters in the given function with letters:

$y=A(Bx)-C$

Then, in the given function A = - 1, B = 1/2, and C = -3.

Now, you can write the parent function:

$y=1.cos(1.x)+0$

Then, the parameters are A = - 1, B = 1, and C = 0.

3 0

3 years ago

What goes in the boxes?

Anna [14]

Answer: machine 1: 3/5 machine 2: 3/4

machine 1 is working at a faster rate

Step-by-step explanation:

5 0

3 years ago

I need help please! Step by step

nevsk [136]

The total length was 6 m.

One of the tables was 1.8 m

Subtract 1.8 from 6 to find the total length of the other two tables:

6 - 1.8 = 4.2m

The other two tables are the same size, so now divide 4.2 m by 2:

4.2 / 2 = 2.1

The other tables are 2.1 m long.

6 0

3 years ago

Jacob solves the system of equations by forming a matrix equation.

Lyrx [107]

Simultaneous equations can be solved using inverse matrix operation.

The complete steps of Jacob's solution are:

$\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]^{-1} \cdot \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14}\left[\begin{array}{cc}3&-1\\2&4\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]$

$\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}4&1\\-2&3\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]$

$\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14} \left[\begin{array}{c}28&-84\end{array}\right]$

$\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{c}2&-6\end{array}\right]$

We have:

$4x + y = 2$

$-2x + 4y = -22$

Calculate the determinant of $\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]$

$|A| = 4 \times 3 -1 \times -2$

$|A| = 12 +2$

$|A| = 14$

So, the inverse matrix becomes

$A = \frac{1}{14}\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]$

Replace the first column with $\left[\begin{array}{c}2&-22\end{array}\right]$ to calculate the value of x

$x = \frac{1}{14}\left[\begin{array}{cc}2&1\\-22&3\end{array}\right]$

So, we have:

$x = \frac{1}{14}(2 \times 3 - 1 \times -22)$

$x = \frac{1}{14}(6 +22)$

$x = \frac{1}{14}(28)$

$x = 2$

Replace the second column with $\left[\begin{array}{c}2&-22\end{array}\right]$ to calculate the value of y

$y = \frac{1}{14}\left[\begin{array}{cc}4&2\\-2&-22\end{array}\right]$

So, we have:

$y = \frac{1}{14}(4 \times -22 - 2 \times -2)$

$y = \frac{1}{14}(-88 +4)$

$y = \frac{1}{14}(-84)$

$y = -6$

Hence, the complete process is:

$\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}4&1\\-2&3\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]$

$\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14} \left[\begin{array}{c}28&-84\end{array}\right]$

$\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{c}2&-6\end{array}\right]$