1. B
2. D
3. C= πD
a) 204π or 641 cm
A= π r²
b) π (102)²
10404π squared cm or 32669 squared cm
4. C
5. D
Given:
pool length : 10 yards
pool width : 8 yards
Area = 10 yds * 8 yds = 80 yd²
(10 + 2x)(8 + 2x) = 120
10(8 + 2x) + 2x(8+2x) = 120
80 + 20x + 16x + 4x² = 120
4x² + 36x + 80 - 120 = 0
4x² + 36x - 40 = 0
4(x² + 9x - 10) = 0
4(x + 10)(x - 1) = 0
x + 10 = 0
x = -10
x - 1 = 0
x = 1
the width of the deck is 1 yard
Answer:
Step-by-step explanation:
Y= -4x+8.... all u had to do is subtract 4x to the other side and get that answer
