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lyudmila [28]
2 years ago
10

Idek the answer please help

Mathematics
2 answers:
VashaNatasha [74]2 years ago
4 0

Answer:

A.

Step-by-step explanation:

VMariaS [17]2 years ago
3 0

y⁵ ÷ y⁹

= y⁵-⁹

= y-⁴ [ 3rd answer ]

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The pyramid of khagra,in Egypt,is 488 feet tall. The Eiffel Tower,in France,is 1,063 feet tall. How much taller is the Eiffel To
steposvetlana [31]

Answer:

The Eiffel Tower in France is 575 feet taller than pyramid of khagra.          

Step-by-step explanation:

We are given the following in the question:

Height of pyramid of khagra = 488 feet

Height of Eiffel Tower in France = 1,063 feet

Difference in height =

= Height of Eiffel Tower in France - Height of pyramid of khagra

=1063 - 488\\= 575\text{ feet}

Thus, the Eiffel Tower in France is 575 feet taller than pyramid of khagra.

7 0
3 years ago
A person’s website specializes in the sale of rare or unusual vegetable seeds. He sells packets of sweet-pepper seeds for $ 2.48
Anon25 [30]
Why would rare vegetable seeds be that cheap
5 0
3 years ago
Evaluate the function for <br> f(5)=4x+3<br><br> A. 23 <br> B. 22 <br> C. 18<br> D. 7
Reptile [31]

Answer:

B. 22

Step-by-step explanation:

Hope this helps! Ask me anything if you have any quistions!

6 0
3 years ago
Write the sentence as an equation
mel-nik [20]
Is there any answer choices so I can choose?
8 0
3 years ago
Find the intersection points using substitution or elimination for each system of equations:
natka813 [3]

Answer:

Step-by-step explanation:

Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.

Problem 1:

(x²)/4 +y²= 1

y= x+1

*substitute for y*

Now we have a one-variable equation we can solve-

x²/4 + (x+1)² = 1

x²/4 + (x+1)(x+1)= 1

x²/4 + x²+2x+1= 1

*subtract 1 from both sides to set equal to 0*

x²/4 +x^2+2x=0

x²/4 can also be 1/4 * x²

1/4 * x² +1*x² +2x = 0

*combine like terms*

5/4 * x^2+2x+ 0 =0

now, you can use the quadratic equation to solve for x

a= 5/4

b= 2

c=0

the syntax on this will be rough, but I'll do my best...

x= (-b ± √(b²-4ac))/(2a)

x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))

x= (-2 ±√(4-0))/(2.5)

x= (-2±2)/2.5

x will have 2 answers because of ±

x= 0 or x= 1.6

now plug that back into one of the equations and solve.

y= 0+1 = 1

y= 1.6+1= 2.6

Hopefully this explanation was enough to help you solve problem 2.

Problem 2:

x² + y² -16y +39= 0

y²- x² -9= 0

6 0
3 years ago
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