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lyudmila [28]
3 years ago
10

Idek the answer please help

Mathematics
2 answers:
VashaNatasha [74]3 years ago
4 0

Answer:

A.

Step-by-step explanation:

VMariaS [17]3 years ago
3 0

y⁵ ÷ y⁹

= y⁵-⁹

= y-⁴ [ 3rd answer ]

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loris [4]

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There is only B. one solution

Step-by-step explanation:

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4 0
3 years ago
Please Help me ASAP !!!!!
Annette [7]

Answer:

The graph of the two equations intersect each other at two places.

Step-by-step explanation:

The given equations are

\left \{ {{y=6x^2+1} \atop {y=x^2+4}} \right.

The first equation is the graph of the parent function; y=x^2 shifted  up 1 unit and compressed by a factor of 6.

The second equation is the graph of the parent function; y=x^2 shifted  up 4 units.

The two graphs will intersect each other at;

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3 0
3 years ago
The formula for the surface area of a cylinder is 2\pi r(r+h)2πr(r+h)2, pi, r, left parenthesis, r, plus, h, right parenthesis w
NNADVOKAT [17]

Answer:

2pi x 10 x 210

Step-by-step explanation:

4 0
3 years ago
The owner of a automobile repair center purchased new electronic diagnostic equipment for $12000. He paid 10 precent down and th
jek_recluse [69]
<span>The owner of a automobile repair center purchased new electronic diagnostic equipment for $12000. He paid 10 pERcent down and then paid 60 pAYMENTS monthly of $203.81.

Net loan, P=12000*0.9=10800 
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Number of payments, n=60

Let i=APR

A=P(i/12*(1+i/12)^n)/((1+i/12)^n-1)
Substituting values
203.81=10800(i/12*(1+i/12)^60)/((1+i/12)^n-1)

=>
12*203.81/10800=i(1+i/12)^60/((1+i/12)^60-1)

To solve for i, we form the iterative equation:
</span>(1+i/12)^60=(12*203.81/10800)/i*((1+i/12)^60-1)
i=12*(12*203.81/10800*((1+i/12)^60-1)/i)^(1/60-1)
try i=0.05, 
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Therefore the APR is 5%
8 0
3 years ago
Solving quadratic equations by factoring <br> m(m-3)=0
KatRina [158]
Because it has already been factored, we can solve it straight away. Now, since m is a variable, we yield the same result if m = 0 or m = 3 because we have two components to this equation.

We can either have m = 0 or m - 3 = 0
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6 0
3 years ago
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