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Lesechka [4]
2 years ago
9

A linear function graph has a dotted diagonal line passing through the x-axis at (3, 0), and the y-axis at (0, minus 2) In the f

unction above, the slope will be multiplied by -4, and the y-value of the y-intercept will be decreased by 1 unit. Which of the following graphs best represents the new function? A linear function graph has a diagonal line passing through the x-axis at (1.5, 0), and the y-axis at (0, minus 3) W. A linear function graph has a diagonal line passing through the x-axis at (0.5, 0), and the y-axis at (0, minus 1) X. A linear function graph has a dotted diagonal line passing through the x-axis at (minus 0.5, 0), and the y-axis at (0, minus 1) Y. A linear function graph has a diagonal line passing through the x-axis at (minus 1.5, 0), and the y-axis at (0, minus 3)
Mathematics
1 answer:
Delicious77 [7]2 years ago
4 0

The graph which best represents the new function is a linear function on a coordinate plane as shown in the image below.

<h3>How to determine the graph of the new function?</h3>

First of all, we would determine the slope of the linear function as follows:

Slope, m = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope, m = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}\\\\Slope, m = \frac{-2\;-\;0}{0\;-\;3}

Slope, m = ⅔.

Multiplying by -4, the new slope is:

Slope = ⅔ × -4

Slope = -8/3 or 2.7.

For the equation of this line, we have:

y - y₁ = m(x - x₁)

y - 0 = -8/3(x - 3)

y - 0 = -8/3x + 8

y = -8/3x + 8

Decreasing the y-value by 1, we have:

y = -8/3x + 8

y = -8/3x + 8 - 1

y = -8/3x + 7

Therefore, we would have a linear function on a coordinate plane as shown in the image attached below.

Read more on slope here: brainly.com/question/17601248

#SPJ1

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gavmur [86]

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Yes, parallelogram OABC is a rectangle.

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3 years ago
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