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Lesechka [4]
2 years ago
9

A linear function graph has a dotted diagonal line passing through the x-axis at (3, 0), and the y-axis at (0, minus 2) In the f

unction above, the slope will be multiplied by -4, and the y-value of the y-intercept will be decreased by 1 unit. Which of the following graphs best represents the new function? A linear function graph has a diagonal line passing through the x-axis at (1.5, 0), and the y-axis at (0, minus 3) W. A linear function graph has a diagonal line passing through the x-axis at (0.5, 0), and the y-axis at (0, minus 1) X. A linear function graph has a dotted diagonal line passing through the x-axis at (minus 0.5, 0), and the y-axis at (0, minus 1) Y. A linear function graph has a diagonal line passing through the x-axis at (minus 1.5, 0), and the y-axis at (0, minus 3)
Mathematics
1 answer:
Delicious77 [7]2 years ago
4 0

The graph which best represents the new function is a linear function on a coordinate plane as shown in the image below.

<h3>How to determine the graph of the new function?</h3>

First of all, we would determine the slope of the linear function as follows:

Slope, m = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope, m = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}\\\\Slope, m = \frac{-2\;-\;0}{0\;-\;3}

Slope, m = ⅔.

Multiplying by -4, the new slope is:

Slope = ⅔ × -4

Slope = -8/3 or 2.7.

For the equation of this line, we have:

y - y₁ = m(x - x₁)

y - 0 = -8/3(x - 3)

y - 0 = -8/3x + 8

y = -8/3x + 8

Decreasing the y-value by 1, we have:

y = -8/3x + 8

y = -8/3x + 8 - 1

y = -8/3x + 7

Therefore, we would have a linear function on a coordinate plane as shown in the image attached below.

Read more on slope here: brainly.com/question/17601248

#SPJ1

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Step-by-step explanation:

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Marina86 [1]
<h2 /><h2>⟹</h2>

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

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Equation at the end of step 1

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Pull out like factors :

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Equation at the end of step3:

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Equations which are never true:

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This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

Solve : y-4 = 0

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3 years ago
Which three values are greater than
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Answer:

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45% = 9/20 is less than 1/2

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0.62 is greater than 1/2

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You work in the HR department at a large franchise. you want to test whether you have set your employee monthly allowances corre
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Answer:

1) Null hypothesis:\mu \leq 500  

Alternative hypothesis:\mu > 500  

z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90  

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

z_{crit}= 2.33

For this case we see that the calculated value is higher than the critical value

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

2) Since is a right tailed test the p value would be:  

p_v =P(z>5.90)=1.82x10^{-9}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

Step-by-step explanation:

Part 1

Data given

\bar X=640 represent the sample mean

\sigma=150 represent the population standard deviation

n=40 sample size  

\mu_o =500 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Step1:State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 500, the system of hypothesis would be:  

Null hypothesis:\mu \leq 500  

Alternative hypothesis:\mu > 500  

Step 2: Calculate the statistic

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

We can replace in formula (1) the info given like this:  

z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90  

Step 3: Calculate the critical value

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

z_{crit}= 2.33

Step 4: Compare the statistic with the critical value

For this case we see that the calculated value is higher than the critical value

Step 5: Decision

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

Part 2

P-value  

Since is a right tailed test the p value would be:  

p_v =P(z>5.90)=1.82x10^{-9}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

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Answer:

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Step-by-step explanation:

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