4(5x+1)(5x-1) = 0
1. Take out the GCF (in this case, 4)
4(25x^2-1) = 0
2. This can be further factored. Factor the values within the parenthesis
4(5x + 1)(5x -1) = 0
25-4x=16-4x
25-4x+4x=16-4x+4x
25=16
No solution
Contradiction
A.
<span>GCF(10; 2) = 2 /</span>factors of 10: 1, 2, 5, 10; factors of 2: 1, 2/
B.
GCF(4; 6) = 2 /factors of 4: 1, 2, 4; factors of 6: 1, <span>2, 3, 6/</span>
C.
GCF(6; 12) = 6 /factors of 6: 1, 2, 3, 6; factors of 12: 1, <span>2, 3, 4, 6, 12/</span>
D.
GCF(2; 24) = 2 <span>/factors of 2: 1, 2; factors of 24: 1, <span>2, 3, 4, 6, 8, 12, 24/</span>
</span>Answer: A, B and D.
Answer:
(1-cosA)/(1+cosA)
=(1-cosA)/(1+cosA) ×(1-cosA)/(1-cosA)
=(1-cosA)^2 /(1-cos^2A)
=(1-cosA)^2 / (sin^2A)
=(1/sinA - cosA/sinA )^2
=cosecA - cotA)^2
Hope it helps
Have a great Day ; )
He score 48 marks.
This can be found by simply multiplying 80 by 60% (0.6). This will give you your rinal answer of 48.
I hope this helps!
