For the following right triangle, find the side length x. Round your answer to the nearest hundredth.

Mathematics

1 answer:

Aleksandr [31]3 years ago

7 0

Answer:

x = 9

Step-by-step explanation:

$a^{2} = c^{2} - b^{2}$

$a^{2} = 15^{2} - 12^{2}$

$a^{2} = 225 - 144$

$a^{2} = 81$

$\sqrt{a^2} = \sqrt{81}$

$a = 9$

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The expression on the left side of an equation is show below

max2010maxim [7]

Answer:

−4(x−2)+5x

Distribute:

=(−4)(x)+(−4)(−2)+5x

=−4x+8+5x

Combine Like Terms:

=−4x+8+5x

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8 0

3 years ago

8 was dividedby some numberthen added to13.next this difference was multiplied by 2 which gave a product of 30 find the answer

Anna11 [10]

The answer is 4.

8/x +13 = y --------> y * 2 = 30

divide 2 on both sides so y = 15

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3 years ago

Triangle pqr has vertices p(-3 -1) q(-1,-7) and r(3,3) and points a and b are midpoints of segment pq and segment rq respectivel

Serhud [2]

Answer:

View graph

Step-by-step explanation:

Be: p(-3,-1) q(-1,-7) r(3,3)

we must find the value of the middle point a and b

$a=\frac{pq}{2}\\b=\frac{rq}{2}$

remember that distance between two points is:

$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }$

pq=distance between p and q

qr =distance between q and r $pq=\sqrt{(-1+3)^{2}+(-7+1)^{2}}=\sqrt{(2)^{2}+(-6)^{2}}=\sqrt{40}\\ pq=2\sqrt{10}\\ a=\frac{pq}{2}=\frac{2\sqrt{10}}{2}=\sqrt{10}\\ coordinates\\a=\frac{pq}{2}=\frac{(-3-1,-7-1)}{2}=(-2,-4)\\\\qr=\sqrt{(3+1)^{2}+(3+7)^{2}}=\sqrt{(4)^{2}+(10)^{2}}=\sqrt{116}\\qr=2\sqrt{29}\\ b=\frac{qr}{2}=\frac{2\sqrt{29}}{2}=\sqrt{29}\\ coordinates\\b=\frac{pq}{2}=\frac{(-1+3,-7+3)}{2}=(1,-2)\\$