Which graph shows a function whose domain and range exclude exactly one value?

Mathematics

2 answers:

VladimirAG [237]3 years ago

7 0

Answer:

C (the third graph)

Step-by-step explanation:

This graph's function has a domain and range that both exclude one value, which is 0. The x and y values are never 0 in the function, as it approaches 0 but never meets it.

tiny-mole [99]3 years ago

3 0

Answer:

see below

Step-by-step explanation:

This graph has an asymptote at y = 0 and x=0

This excludes these values

The domain excludes x =0

The range excludes y=0

You might be interested in

Can y’all help me on question 16?!

Zina [86]

600kb in 24 seconds to find out how many kbs per second divide by 24
600/24 is 25kb

6 0

2 years ago

Write "x is less than or equal to zero" three different ways.

garik1379 [7]

The expression "x is less than or equal to zero" can be written in several forms; some examples, however, could be:

x ≤ 0
0 ≥ x
(You could substitute any number in place of 3 for the below)
3 - 3 ≥ x

3 0

2 years ago

Factor the binomial: 24mn + 32m *

8_murik_8 [283]

The greatest common multiple is 8m, so this means that you can factor it out to:

=8m(3n+4)
=(8m•3n)+(8m•4)
=(24mn)+(32m)
=24mn+32m

The answer is option 2.

4 0

3 years ago

3x^2 + 4x = -8 solve using quadratic formula

Firdavs [7]

Use the quadratic equation to solve this (image of the quadratic equation is below)

Remember that quadratic functions are set up like so:

$ax^{2} +bx +c = 0$

To make the equation 3x² + 4x = -8 into a quadratic function you must bring -8 to the left side of the equation so it equals zero. To do this add 8 to both sides

3x² + 4x + 8= -8 + 8

3x² + 4x + 8 = 0

That means that in this equation...

a = 3

b = 4

c = 8

^^^Plug these numbers into the quadratic equation and solve (Keep in mind that +/- is ± )

$\frac{-4+/-\sqrt{(4)^{2}-4(3)(8)}}{2(3)}$