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3 years ago

Determine if the sequence is arithmetic write yes or no 5,9,14,20

Mathematics

1 answer:

makkiz [27]3 years ago

5 0

Answer: No

Step-by-step explanation:

An arithmetic sequence is one where the same number is being added to the number before it. For example, 2, 4, 6, 8..., where 2 is being added to each number.

In this case, however, the number being added is not consistent with this pattern. Between 5 and 9, the difference is 4 and between 9 and 14, the difference is 5, and so forth. This pattern does not follow the rules of an arithemtic sequence.

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RQ= x+1 QP=7 RP=2x+8 solve for RP

a_sh-v [17]

Answer:

RP = 8

Step-by-step explanation:

RQ + QP = RP (segment addition theorem)

(x + 1) + 7 = 2x + 8 (substitution)

Add like terms

x + 8 = 2x + 8

8 - 8 = 2x - x

0 = x

x = 0

✔️RP = (x + 1) + 7

Plug in the value of x

RP = (0 + 1) + 7

RP = 1 + 7

RP = 8

5 0

3 years ago

Which of the following will result in a rational answer?

Varvara68 [4.7K]

Answer

B. adding the square root of a non perfect square to a whole number

P.S
Non-perfect square roots as rational numbers

7 0

4 years ago

Read 2 more answers

You play a game of chance that you can either win or lose (there are no other possibilities) until you lose. Your probability of

DanielleElmas [232]

Answer:

Step-by-step explanation:

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5 0

3 years ago

Find how long it takes a $ 900.00 investment to earn $ 120.00 in interest if it is invested at 6% compounded annually.

atroni [7]

So, we know the earned interest is 120, and we know the original deposited amount is 900 bucks, so, the accumulated amount will then be 900 + 120 or 1020 bucks.

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$1020\\
P=\textit{original amount deposited}\to &\$900\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years
\end{cases}$

$\bf 1020=900\left(1+\frac{0.06}{1}\right)^{1\cdot t}\implies \cfrac{1020}{900}=(1.06)^t\implies \cfrac{102}{90}=(1.06)^t
\\\\\\
log\left(\frac{102}{90} \right)=log(1.06^t)\implies log\left(\frac{102}{90} \right)=t\cdot log(1.06)
\\\\\\
\cfrac{log\left(\frac{102}{90} \right)}{log(1.06)}=t\implies 20.92 \approx t$

7 0

4 years ago

Swimming Pool On a certain hot summer's day, 630 people used the public swimming pool. The

crimeas [40]

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the linear equation in two variables.

So we have to form two equations to solve this.

Let the number of children be 'x' and number of adults be 'y'.

hence, we get as,

x+y = 630 ..... (1)

and also, to their total cost spending, we get as,

1.5x + 2.25y = 1170 ...... (2)

solving (1) and (2) we get as,

Number of children were = 330

and Number of Adults were = 300

(Solved in the attachment)

4 0

4 years ago