1,280 at 3% compounded annually for 3 years

lutik1710 [3]

2+2 = 4. Bro it was so hard. Did i helped you?

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=5x%20%7B%7D%5E%7B2%7D%20%5Cdiv%20%5Csqrt%7B2%20%7D%20%3D%20164" id="TexFormula1" title="5x {}^

umka2103 [35]

Answer:

The short answer is : x=6.81

Step-by-step explanation:

First thing to do is multiply in $\sqrt{2}$

<h3>To Until it become :</h3>

$5x {} ^{2} =164 * \sqrt {2}$

Now we will divided on 5 and calculate the numper to it equal 46.3

Then you will take square root To the two parties

To equal in the end =6.81

6 0

3 years ago

help me... the angle pairs.. for example linear pair, vertical angles... that stuff.... I said that because last time I asked th

Cerrena [4.2K]

<h3>Answers: </h3>

Angle 1 and 3: Vertical Angles

Angle 4 and 8: Corresponding Angles

Angles 4 and 6: Alternate Interior Angles

Angles 3 and 5: Alternate Interior Angles

Angles 7 and 8: Linear Pair

Angles 1 and 7: Alternate Exterior Angles

=================================================

Explanation:

Vertical angles are formed when you cross two lines to form an X shape. The vertical angles are opposite one another in this configuration.

Corresponding angles are ones that show up in the same corner of each four-corner crossing. In the case of angles 4 and 8, both are in the southwest corner of each four-corner crossing.

Alternate interior angles are angles in between parallel lines and on opposite sides of a transversal. Alternate exterior angles are similar, but they are outside the parallel lines.

A linear pair of angles are adjacent and supplementary (meaning they add to 180).

8 0

3 years ago

Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha

Pavel [41]

Answer:

$(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14$ .

(Expand to obtain an equivalent expression for the sphere: $x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ )

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

$\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}$ .

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

$\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}$ .

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between $\left(x_1, \, y_1, \, z_1\right)$ and $\left(x_2, \, y_2, \, z_2\right)$ would be:

$\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right)$ .

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

$\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}$ .

The equation for a sphere of radius $r$ and center $\left(x_0,\, y_0,\, z_0\right)$ would be:

$\left(x - x_0\right)^2 + \left(y - y_0\right)^2 + \left(z - z_0\right)^2 = r^2$ .

In this case, the equation would be:

$\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z - (-6)\right)^2 = \left(\sqrt{56}\right)^2$ .

Simplify to obtain:

$\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z + 6\right)^2 = 56$ .

Expand the squares and simplify to obtain:

$x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0$ .

8 0

3 years ago

Solve this system of equations: y = x2 – 3x + 12 y = –2x + 14 1.Isolate one variable in the system of equations, if needed. y =

lina2011 [118]

-2x+14=x²-3x+12
add 2x on both side:
14=x²-x+12
subtract 14 on both side:
x²-x-2=0
factor: (x-2)(x+1)=0
x=2 or x=-1
HOPE THIS HELPS AND PLEASE MARK ME AS BRAINIEST AND ADD ME AS A FRIEND

8 0

4 years ago

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