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3 years ago

Y-3=2 (x+1) what is this i need it for knah

Mathematics

1 answer:

Bezzdna [24]3 years ago

6 0

The equation simplified is y=2x+5

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In a metal fabrication process, metal rods are produced to a specified target length of 15 feet. Suppose that the lengths are n

Leto [7]

Answer:

95% Confidence interval: (14.4537 ,15.1463)

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 feet

Sample mean, $\bar{x}$ = 14.8 feet

Sample size, n = 16

Alpha, α = 0.05

Sample standard deviation, σ = 0.65 feet

Degree of freedom = n - 1 = 15

95% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 15 and}~\alpha_{0.05} = \pm 2.1314$

$14.8 \pm 2.1314(\dfrac{0.65}{\sqrt{16}} ) \\\\= 14.8 \pm 0.3463 = (14.4537 ,15.1463)$

is the required confidence interval for the true mean length of rods.

3 0

4 years ago

Read 2 more answers

The length of a rectangle is 12 inches longer than the width. Find the length and width if the perimeter is 184 inches.

solong [7]

Perimeter = 2l + 2w

Divide 184 by 4

184/4 = 46

Subtract by 6

46 - 6 = 40

Add by 6

46 + 6 = 52

The length is 52, and the width is 40.

We can verify by plugging these values into the original equation.

52*2 + 40*2 = 184

3 0

4 years ago

Estimate the product.<br><br> 5/6 x 10/13

EleoNora [17]

Do you simplify it or multiply it?

8 0

3 years ago

What is the first step in solving the inequality m-2/6 < -1?

Softa [21]

Answer:

i think its b

Step-by-step explanation:

because you have to add or subtract on both sides

3 0

4 years ago

From the sum of a2−2ab+b2 and 2a2+2ab+b2 subtract the sum of a2−b2 and a2+ab+3b2

Sedaia [141]

Answer:

$a^2-ab$

Step-by-step explanation:

We need to find the sum of $a^2-2ab+b^2$ and $2a^2+2ab+b^2$ first.

Adding $a^2-2ab+b^2$ + $2a^2+2ab+b^2$

Combining like terms, we get

$a^2+2a^2=3a^2$

-2ab+2ab = 0

$b^2+b^2=2b^2$

Therefore,

$a^2-2ab+b^2 +2a^2+2ab+b^2=3a^2+2b^2$ .

Now, we need to find the sum of $a^2-b^2 \ \ and \ \ a^2+ab+3b^2.$ .

Adding $a^2−b^2+a^2+ab+3b^2$ .

Combining like terms, we get

$a^2+a^2=2a^2$

$-b^2+3b^2=2b^2$ .

Therefore,

$a^2−b^2+a^2+ab+3b^2=2a^2+ab+2b^2.$

Now, subtracting

$3a^2+2b^2 -(2a^2+ab+2b^2)$ .

Distributing minus sign over second parenthesis, we get

$3a^2+2b^2-2a^2-ab-2b^2$ .

Combining like terms,

$3a^2-2a^2=a^2$

$2b^2-2b^2=0$

Therefore,

$3a^2+2b^2-2a^2-ab-2b^2=a^2-ab$ .

Therefore, the difference of the sum of $a^2-2ab+b^2$ + $2a^2+2ab+b^2$ and $a^2-b^2+a^2+ab+3b^2.$ is $a^2-ab.$

5 0

3 years ago