You use the equation Final Velocity²= (Initial Velocity)² 2(Acceleration)(Distance). You plug in what you have 0²=22.4² X 2(-3.5)(D) and solve for D which is 71.68m or about 72m.

6 0

2 years ago

CORRECT THE ERROR 1) 4a^(2)*3a^(5)=(4+ 3)a^(2+5)=7a^(7) // 2) x^(6)x*x^(3)=6^(4+3) //

Natasha2012 [34]

Answer:

Step-by-step explanation:

8 0

2 years ago

The logo for Chris's Calculator Company is 3 semicircles. The logo will be placed on the company building and will be 4 feet tal

Keith_Richards [23]

Answer:

The area of the logo is $18.84\ ft^{2}$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The area of a semicircle is equal to

$A=\frac{1}{2}\pi r^{2}$

The area of the logo is equal to multiply by 3 the area of one semicircle

$A=\frac{3}{2}\pi r^{2}$

we have

$r=4/2=2\ ft$ -----> the radius is half the diameter

substitute

$A=\frac{3}{2}(3.14)(2)^{2}=18.84\ ft^{2}$

8 0

3 years ago