Standardised z score = (16.075 - 16) / 0.2 = 0.375
which gives a probability of 0.1462 for selecting a package of weight 16.075
the probability of weight being excess of 16.075 = 0.5 - 0.1462 = 03538
Probability of picking 16 in excess of 16-075 = 0.3538^16 = 6.0273 * 10^-8
Answer: sorry
Step-by-step explanation:
There isn't enough information for anyone to answer, sorry.
Answer:
True
Step-by-step explanation:
They are parallel because they will never intersect.
Hope this helps!
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Correct me if my answer
is incorrect, thank you!
The two traingles, VSU and TSR are similar by SAS similarity criteria.
According to the diagram,
UT = TS
and
VR = SR
Similarly for all sides the ratio must be same.
Applying this on the side required here,
Therefore p = 12 units= UV .
<em>In total 5 days, she has paid:</em> <em>5 x $2 = $10 </em><em>for the sandwiches</em>
<em>In total 5 days, she has paid: </em><em>$50 - $10 = $40 </em><em>for the comics</em>
<em>So, she paid: </em>$40 / 5 = $8<em> for each comic</em>
<em>If helpful, brainliest please !</em>
