Answer:
Midpoint = (3.5, 4.5)
Perpendicular bisector = y = 
x + 
Step-by-step explanation:
[] We can solve this using the midpoint formula:
-> See attached
[] Plug-in our coordinates and solve:
[] Now we will find the slope to solve for the perpendicular bisector.
-> We will use slope-intercept form, see attached
-> The slopes of two perpendicular lines are negative reciprocals of each other, so will be the slope of or perpendicular bisector
-> Now we can solve for the equation by using y – y1 = m ( x – x1), were y1 and x1 are the coordinates of our midpoint
y - 4.5 = (x-3.5)
y - 4.5 = x-
y = x- + 4.5
y = x +
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer:
y = (2/5) OR y = (6/5)
Step-by-step explanation:
The first step is isolating the expression within the absolute value bars. The first thing we can do is subtract both sides by 8. If we do that, we get -2|4-5y| = -4. Now, to completely isolate the absolute value, we would have to divide by -2. This yields |4 - 5y| = 2. Finally, we can remove the absolute value bars. However, to do this, we need to first understand what an absolute value bar does to an equation. Lets say that |x| = 2. Absolute value describes the DISTANCE of some quantity from 0 (on the number line). Therefore, x (which is inside the absolute value bars) can be either positive or negative 2 (they are BOTH two units away from 0). Similarly, in this case, (4 - 5y) can either be 2 or -2 (because the absolute value of both is 2). Now we have two possible solutions to solve for:
4 - 5y = 2 OR 4 - 5y = -2
5y = 2 OR 5y = 6
y = (2/5) OR y = (6/5)
If we plug both of these answers back into the equation we can see that they both check out.
Answer: 180
Angles in a linear pair are always supplementary. This means they form a straight angle or a straight line.
Answer:
21%
Step-by-step explanation:
15/70=21.14 round to 21
Answer:
The chosen topic is not meant for use with this type of problem. Try the examples below.
√x+2=3
−4+y=3y+4(y−3)
2+|3x|=2+3
