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Romashka [77]
3 years ago
11

What’s the equation for the table?

Mathematics
1 answer:
polet [3.4K]3 years ago
7 0
(25, 160) and (50, 320)
(y2-y1)/(x2-x1)
(320-160)/(50-25)
160/25 = slope
Y = 6.4x + b
Plug in points and solve for b
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What’s is ittttt I neeed helppp
Softa [21]

Answer:

n = 14

Step-by-step explanation:

n+4/-2 = -9

n+4 = 18

n = 14

5 0
4 years ago
Read 2 more answers
B) If A (-3, 2) is translated by
Alona [7]

Answer:

A'(-6,4)

Step-by-step explanation:

A transformation of  (x, y) → (x-3, y + 2)  means:

  • x coordinate gets translated 3 units left [we subtract 3 from original x coordinate]
  • y coordinate gets translated 2 units up [we add 2 to original y coordinate]

The original x coordinate is -3 so we subtract 3 from it to get:

New x = -3 -3 = -6

The original y coordinate is 2 so we add 2 to get:

New y = 2 + 2 = 4

So A' is

A'(-6,4)

5 0
3 years ago
Find the average rate of change of each function over the interval [0, 2]. Match each representation with its respective average
marishachu [46]
Average rate of change over interval [a,b]: r=[f(b)-f(a)]/(b-a)
In this case the interval is [0,2], then a=0, b=2
r=[f(2)-f(0)]/(2-0)
r=[f(2)-f(0)]/2

1) First function: h(x)
r=[h(2)-h(0)]/2
x=2→h(2)=(2)^2+2(2)-6
h(2)=4+4-6
h(2)=2
x=0→h(0)=(0)^2+2(0)-6
h(0)=0+0-6
h(0)=-6
r=[h(2)-h(0)]/2
r=[2-(-6)]/2
r=(2+6)/2
r=(8)/2
r=4

2) Second function: f(x)
A function, f, has an
x-intercept at (2,0)→x=2, f(2)=0
and a y-intercept at (0,-10)→x=0, f(0)=-10
r=[f(2)-f(0)]/2
r=[0-(-10)]/2
r=(0+10)/2
r=(10)/2
r=5

3) Third function: g(x)
r=[g(2)-g(0)]/2
From the graph:
g(2)=6
g(0)=2
r=(6-2)/2
r=(4)/2
r=2

4) Fourth function: j(x)
r=[j(2)-j(0)]/2
From the table:
x=2→j(2)=-8
x=0→j(0)=4
r=(-8-4)/2
r=(-12)/2
r=-6

Answer:
Pairs
1) h(x)     4
2) f(x)      5
3) g(x)     2
4) j(x)     -6
8 0
4 years ago
Giúp tớ giải bài toán này với
vampirchik [111]

Answer:

english pls

Step-by-step explanation:

6 0
3 years ago
The function y= x2 - 10x+ 31 has a<br> value of
Margarita [4]

Answer:

  • y = 6 at x = 5

Step-by-step explanation:

It is assumed the question is about finding the minimum value as the given function has no maximum value, it is + ∞ as the coefficient of x² is positive

<u>The minimum/maximum value of a quadratic function is the vertex, which is at:</u>

  • x = -b/2a

<u>For the given function y = x² -10x + 31, the vertex is:</u>

  • x =  - (-10)/2*1 = 10/2 = 5

<u>The value of y at this point is:</u>

  • y = 5² - 10*5 + 31 = 25 - 50 + 31 = 6

<u>The point is </u>

  • (5, 6)

5 0
3 years ago
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