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3 years ago

What’s the equation for the table?

Mathematics

1 answer:

polet [3.4K]3 years ago

7 0

(25, 160) and (50, 320)
(y2-y1)/(x2-x1)
(320-160)/(50-25)
160/25 = slope
Y = 6.4x + b
Plug in points and solve for b

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1. 9c-3c=48A) c=9B) c=3C) c=4D) C=8

Alona [7]

$9c\text{ - 3c = 48}$

To solve this equation, we need to subtract both, 9c - 3c:

$9c\text{ - 3c = 6c = 48}$

Dividing by 6 at both sides of the equation

$\frac{6c}{c}\text{ = }\frac{48}{6}$

Then

$c\text{ = 8}$

Then the answer C = 8. (Option D)

3 0

1 year ago

Simplify the expression -6 - 6F + 7 - 3f - 9

Pie

-8-6f-3f = -8-9f
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3 years ago

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Ber [7]

Answer: width = 72.50 m

Step-by-step explanation:

P = 2l + 2w

425 = 2( 140 ) + 2w

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5 0

3 years ago

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Nikitich [7]

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3 years ago

Eli attended a concert. The decibel level of the music averaged 110 decibels but varied by 28 decibels from the average. Enter a

musickatia [10]

Answer:

The decibel range is $82\leq d\leq 138$

Step-by-step explanation:

Let

d -----> the decibel level of the music

we know that

The absolute value of the difference of the decibel level of the music and its average, must be less than or equal to 28 decibels

The absolute value that represent this problem is

$\left|d-110\right|\le28$

Solve the absolute value

First solution (positive)

$+(d-110)\le28$

Adds 110 both sides

$d\le28+110$

$d\le138$

Second solution (negative)

$-(d-110)\le28$

Multiply by -1 both sides

$(d-110)\ge-28$

Adds 110 both sides

$d\ge-28+110$

$d\ge82$

therefore

The decibel range is

$82\leq d\leq 138$

8 0

4 years ago