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3241004551 [841]
3 years ago
8

Solve by using elimination 3x-2y=1. 8x+3y=2

Mathematics
1 answer:
Kitty [74]3 years ago
3 0
Elminate the y's
multiiply first euation by 3 and multiply 2nd equation by 2 and ad them

9x-6y=3
<u>16x+6y=4 +</u>
25x+0y=7

25x=7
divide both sides by 25
x=7/25
sub back

3x-2y=1
3(7/25)-2y=1
21/25-2y=1
note: 1=25/25
minus 21/25 fromboth sides
-2y=4/25
divide both sides by -2 (or times -1/2)
y=4/-50
y=-2/25

x=7/25
y=-2/25

(-2/25,7/25)
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Simplify the following expression, if you can see the picture the expression is as follows:
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\sqrt{40}=2 \sqrt{10} and \sqrt{90} = 3\sqrt{10}, so we have \sqrt{10}(2-1+3). which is 4 \sqrt{10}.
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3 years ago
the value of a new automobile depreciates 15% during the first year, and 16% during the second year. What is its depreciated val
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3 0
3 years ago
Can I have help with the problem in the picture pls​
Bumek [7]
A is the correct answer !
8 0
2 years ago
Suppose that 80% of all trucks undergoing a brake inspection at a certain inspection facility pass the inspection. Consider grou
Gwar [14]

Answer:

P=0.147

Step-by-step explanation:

As we know 80% of the trucks have good brakes. That means that probability the 1 randomly selected truck has good brakes is P(good brakes)=0.8 . So the probability that 1 randomly selected truck has bad brakes Q(bad brakes)=1-0.8-0.2

We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.

We have to find the probability of each event (9, 10 or 11 trucks from 16 will pass the inspection) .  To find the required probability 3 mentioned probabilitie have to be summarized.

So P(9/16 )=  C16 9 * P(good brakes)^9*Q(bad brakes)^7

P(9/16 )= 16!/9!/7!*0.8^9*0.2^7= 11*13*5*16*0.8^9*0.2^7=approx 0.02

P(10/16)=16!/10!/6!*0.8^10*0.2^6=11*13*7*0.8^10*0.2^6=approx 0.007

P(11/16)=16!/11!/5!*0.8^11*0.2^5=13*21*16*0.8^11*0.2^5=approx 0.12

P(9≤x<12)=P(9/16)+P(10/16)+P(11/16)=0.02+0.007+0.12=0.147

7 0
3 years ago
WILL MARK BRAINLIEST, JUST HELP ME PLS
Luda [366]

Answer:

SAS theorem

Step-by-step explanation:

If \frac{CE}{CB} = \frac{DC}{AC} and m∠ECD = m∠BCA, then the triangles are similar by the SAS theorem.

\frac{EC}{BC} =  \frac{14}{21} = \frac{2}{3}           \frac{DC}{AC} = \frac{18}{27} = \frac{2}{3}

So,  \frac{CE}{CB} = \frac{DC}{AC}  and m∠ECD = m∠BCA because vertical angles are congruent

Therefore ΔECD is similar to ΔBCA by SAS theorem

5 0
2 years ago
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