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lutik1710 [3]
3 years ago
11

It takes a car 1.75 h to go from mike marker 10 to mile marker 115. what is the average speed of the car?

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
8 0

Answer:

60 mph

Step-by-step explanation:


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Suppose you borrow 13,000 for four years at 7% toward the purchase of a car.
dangina [55]
Amount borrowed, P = 13000
Interest, i = 0.07/12 per month
number of periods (months),  n = 4*12 = 48

Monthly payment, 
A=\frac{P(i*(1+i)^n)}{(1+i)^n-1}
=\frac{13000(.07/12*(1+.07/12)^{48}}{(1+.07/12)^{48}-1}
=311.30   (to the nearest cent)
5 0
3 years ago
The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

   ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

                    the probability that he will be more than 76 inches tall.

              (b) If two men are chosen at random from the population, find

                    the probability that

                    (i) both of them will be more than 76 inches tall;

                    (ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{S.D}) > \frac{( 76- mean)}{S.D})

                 = P(Z >  \frac{( 76- mean)}{S.D})

                 = P(Z > \frac{76 - 69.7}{2.8})

                 = P(Z > 2.25)

                 = 1 - P(Z  ≤ 2.25)

                 = 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

                                                                           = 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

\frac{S.D}{\sqrt{N} } = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } })) > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- 69.7)}{1.979899 }))

                 = P(Z > 3.182)

                 = 1 - P(Z ≤ 3.182)

                 = 0.0007

⇒P(Y > 76) = 0.0007

6 0
3 years ago
350 people visited a zoo the zoo has four types of tickets the manager wants a sample of size 30, stratified by ticket type. how
NARA [144]

Answer:

The number of teenagers in the stratified sample of equal proportion is 30 teenagers

Step-by-step explanation:

Whereby tickets are sold to only adults male and female and teenagers, boys and girls, we have the following groups

Group 1: Female adult

Group 2: Male adult

Group 3: Teenage boys

Group 4: Teenage girls

In stratified sampling, the types of people that visit the zoo (which is the target population) are identified and the appropriate proportion of each of the identified types is determined such that the sample is representative of the population

Where equal number of each group are observed to have visited the zoo, then, the appropriate sample size of the teenager is found as follows;

Number of groups identified = 4

Sample size = 30

Appropriate proportion of each group = 1/4

Number of teenage boys in the sample = 1/4×30 = 15

Number of teenage girls in the sample = 1/4×30 = 15

Total number of teenagers in the sample = 15 + 15 = 30 teenagers.

5 0
3 years ago
Read 2 more answers
Please help me with this question
MariettaO [177]

Answer:

It would be A,B

Step-by-step explanation:

3 0
3 years ago
The loudness of a jackhammer is a 96 dB. It sounds intense is about _____ . The Loudness of a compactor is 94 dB. It's sound int
aleksandr82 [10.1K]

Answer:

loudness of a jack hammer .004 loudness of a compactor .0025

Step-by-step explanation:

Because edge

8 0
3 years ago
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