All categories

3 years ago

This is a 3 part question, PLEASE HELP ILL GIVE BRAINLY

Mathematics

1 answer:

kaheart [24]3 years ago

7 0

Answer:

Angle of A = 90 degree-62 degree = 28 degree.

Step-by-step explanation:

tan (62) = opposite / adjacent = 10 / a ---> a = 10/tan (62) = 10/ 1.88 = 5.319

cos (62) = a/c --->c = a/cos (62) = 5.319 / 0.47 = 5.3 / 0.47 = 11.3

or another way.

sin (62) = 10 /c ---> c = 10/ sin (62) = 10 / 0.88 = 11.3

So Angle of A = 28 degree.

a = 5. 3

c = 11.3.

please give me brainliest. I hope it help.

You might be interested in

T(d) is a function that relates the number of tickets sold for a movie to the number of days since the movie was released. The a

Xelga [282]

The andwer would be 10 baby

4 0

2 years ago

Read 2 more answers

2. Your teacher tells you that a line goes through the points (-6,1) and (-4, 3). Calculate the slope

Art [367]

Answer:

m=1

Step-by-step explanation:

7 0

3 years ago

What is the square root of four

postnew [5]

The square root of four is two

4 0

3 years ago

PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS ASAP

Alenkasestr [34]

Answer:

(0, 6)

explanation:

original coordinates of C: (5, -6)

if reflected over x-axis, then use the formula: (x,y) → (x, -y)

new coordinates: (5, 6)

then if translated -5 horizontally, there will be change in x axis

new coordinates: (5-5, 6) → (0, 6)

3 0

2 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

3 years ago