3(x+y)=3x+3y is what property

Mathematics

1 answer:

ki77a [65]2 years ago

8 0

Answer:

the answer is distributive property

Step-by-step explanation:

the distributive property tell us that the multiplication of a number (in this case number 3) by a sum (in this case x+y) is equal to the sum of the multiplications of that number by each of the terms belonging to the sum:

3(x+y)=3*x+3*y

3(x+y)=3x+3y

You might be interested in

Standard form for -10-6x^4-7x^2+5x

qaws [65]

-6x^4-7x^2+5x-10. hope this helps ! :)

7 0

2 years ago

Simplify by combining like terms: 15x +2 - 7 - 5x

Step2247 [10]

Answer:

10x-5

Step-by-step explanation:

You subtract 15x-5=10x. Then you do -7+2. The 7 is negative . So it would be -7 plus two. So it would equal -5. So it's 10x-5

5 0

2 years ago

A $104.000 selling price with $24000 down at 8 1/2% for 25 years results in a monthly payment of

romanna [79]

*******************************************************
(See attached formula)
Loan Principal = 104,000 - 24,000 = 80,000
rate = 8.5 / 1,200 = 0.0070833333 
time = 25 years = 300 months

Monthly Payment = 0.0070833333 + [ 0.0070833333 / ((1.0070833333)^300 -1)) ] *principal

Monthly Payment = 0.0070833333 + [ 0.0070833333 / ( 8.3104129461 -1)] * 80,000
Monthly Payment = 0.0070833333 + [ 0.0070833333 / ( 7.3104129461)] * 80,000
Monthly Payment = (0.0070833333 + 0.00096893750767) * 80,000
Monthly Payment = 0.00805227080767 * 80,000
Monthly Payment = 644.18

Source:
http://www.1728.org/calcloan.htm

3 0

2 years ago

Add the decimals represented by the models below.

Bad White [126]

Answer:

im sorry cant help

Step-by-step explanation:

8 0

2 years ago

f the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circular path were reduced, w

LUCKY_DIMON [66]

The frictional force between the tires and the road prevent the car from skidding off the road due to centripetal force.

If the frictional force is less than the centripetal force, the car will skid when it navigates a circular path.

The diagram below shows that when the car travels at tangential velocity, v, on a circular path with radius, r, the centripetal acceleration of v²/ r acts toward the center of the circle.

The resultant centripetal force is (mv²)/r, which should be balanced by the frictional force of μmg, where μ = coefficient of kinetic friction., and mg is the normal reaction on a car with mass, m.

This principle is applied on racing tracks, where the road is inclined away from the circle to give the car an extra restoring force to overcome the centripetal force.

8 0

2 years ago