Answer:
20%×X=30
x=150
Step-by-step explanation:
30÷20%=150
20%×150=30
There would be only 1 pint left of iced tea in the pitcher.
Answer:
d. 3x + 6 = 26
Step-by-step explanation:
<u>Definitions</u>
- Integer: a whole number that can be positive, negative or zero.
e.g. ..., -3, -2, -1, 0, 1, 2, 3, ... - Even number: an integer that is exactly divisible by two. For example, 2, 4, 6, 8 are all positive even numbers.
- Consecutive: following one after the other in order.
<u>The sum of three consecutive even integers</u>
Let x be the first even integer.
As there is a <u>difference of 2</u> between <u>consecutive even integers</u>, the next even integer after x will be (x + 2).
Therefore, the next even integer after (x + 2) will be (x + 2) + 2 = (x + 4).
So "the sum of three consecutive even integers is twenty-six" is:
x + (x + 2) + (x + 4) = 26
<u>To solve</u>
⇒ x + (x + 2) + (x + 4) = 26
⇒ x + x + 2 + x + 4 = 26
⇒ 3x + 6 = 26
(Please note that there are no three consecutive even integers that sum to 26, so the problem cannot be solved).
Answer:
1st Graph
Step-by-step explanation:
A simple way to test if a relation may be taken as a function is by applying the Vertical Line Test. If a Vertical Line crosses the graph only once, then it is a function. In this question, only the first one can be considered to be a function.
Because in other words, only the first graph shows one value for x corresponding to another for y value. Not the case for the second and the third graph displaying two values for x for each y value.
(1) n is not divisible by 2 --> pick two odd numbers: let's say 1 and 3 --> if , then and as zero is divisible by 24 (zero is divisible by any integer except zero itself) so remainder is 0 but if , then and 8 divided by 24 yields remainder of 8. Two different answers, hence not sufficient.
(2) n is not divisible by 3 --> pick two numbers which are not divisible by 3: let's say 1 and 2 --> if , then , so remainder is 0 but if , then and 3 divided by 24 yields remainder of 3. Two different answers, hence not sufficient.
(1)+(2) Let's check for several numbers which are not divisible by 2 or 3:
--> --> remainder 0;
--> --> remainder 0;
--> --> remainder 0;
--> --> remainder 0.
Well it seems that all appropriate numbers will give remainder of 0.
