Answer:
The probability of the event BC
= the probability of B * C = 48.6667% * 70%
= 34.0667%
Step-by-step explanation:
Probability of A, students with children = 44/150 = 29.3333%
Probability of B, students enrolled in at least 12 credits = 73/150 = 48.6667%
Probability of C, students working at least 10 hours per week = 105/150 = 70%
Therefore, the Probability of BC, students enrolled in 12 credits and working 10 hours per week
= 48.6667% * 70%
= 34.0667%
First off, let's convert the mixed fraction to "improper", and divide from there,
Answer:
72
Step-by-step explanation:
Answer:
$60.95
Step-by-step explanation:
First find the total cost of the two meals w/o the tip.
20.25 + 32.75 = 53
Now find what 15% of 53 is by multiply 53 and 0.15 (move the decimal point twice to the left).
53 * 0.15 = 7.95
Add the tip to the total cost of the meals.
53 + 7.95 = 60.95
The total cost is $60.95.
For this problem all it looks like you have to do is multiply 30,000 by 81 to get the total attendance for the 81 home games. Forgive me if I'm wrong but I hope this helps. The answer is 2430000