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Studentka2010 [4]
3 years ago
10

Which expression is equivalent to 3y+4+y

Mathematics
1 answer:
Colt1911 [192]3 years ago
8 0
The answer to this question is 4y+4
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I need help in the two questions
Sholpan [36]
Y-5=3-9 (y+2)
Solve for y
Distribute the 9 to (y+2)
Y-5=3-9y-18
Y-5=-15-9y
+9y to both sides
10y-5=-15
+5 to both sides
10y=-10
÷10 both sides
Y= -1

2 (x-7)-10=12-4x
Solve for X
Distribute 2 to (x-7)
2x-14-10=12-4x
2x-24=12-4x
+4x to both sides
6x-24=12
+24 to both sides
6x=36
÷6 to both sides
X=6
3 0
3 years ago
For each ordered pair (x, y), determine whether it is a solution to the inequality 4x+8y5-8. Is it a solution? Yes No O (6, – 4)
avanturin [10]

Given inequality is:

4x+8y\leq-8

Now for (6,-4), Put x=6 nd y=-4 in given inequality:

\begin{gathered} 4(6)+8(-4)\leq-8 \\ 24-32\leq-8 \\ -8\leq-8 \end{gathered}

So for (6,-4) this inequality is true.

For (-2,-3) put x=-2 and y=-3 in given inequality:

\begin{gathered} 4(-2)+8(-3)\leq-8 \\ -8-24\leq-8 \\ -32\leq-8 \end{gathered}

As -32 is less than -8 then this condition is also true.

simillarly you can check for other options also.

For (-7,5) Put x=-7 and y=5 in given inequality:

\begin{gathered} 4(-7)+8(5)\leq-8 \\ -28+40\leq-8 \\ 12\leq-8 \end{gathered}

As 12 is grater than -8 so this condition is false.

And for (-6,0) put x=-6 and y=0 in given inequality:

\begin{gathered} 4(-6)+8(0)\leq-8 \\ -24\leq-8 \end{gathered}

As -24 is less than -8 so it is true.

4 0
1 year ago
Please Help!! (all three questions!)
Alecsey [184]

Hello there!

24. He had 10 cards at the start.

25. y = 24

26. c = 38

Let's solve each problem:

24.  So Charlie took away 4 and had 6 left, how many did he start with?

Add the 4 taken away back to what is left  - 6 + 4 = 10 So, he had 10 cards at the start.

25. -5y multiplied by what equals 120? To solve, divide 120 by -5. 120/-5 = -24, so y = 24.

26. What minus 11 equals 27? add 11 to 27 to solve. 27 + 11 = 38 so c = 38.

I hope this was helpful! Have a great (rest of your) day!

6 0
3 years ago
Please! Help! The table below shows preferences of dancing or playing sports for male and female students:
Kryger [21]

Answer:

D)   He calculated the joint relative frequency of female students who prefer playing sports. The conditional relative frequency for female students who prefer playing sports is 34%.

Step-by-step explanation:

The table is given as:

                          Playing sports Dancing     Row totals

Male students           18                      16              34

Female students       18                      35             53

Column totals  36                       51               87

  • We know that the joint relative frequency of an outcome is calculated as dividing the frequency of the outcome by the grand total.

Hence, when we divide the frequency of the female students who prefer playing sports i.e. 18 by the grand total i.e. 87 ; we obtain:

18/87=0.20689

which is approximately equal to 21%.

  • Hence, in order to calculate the conditional relative frequencies she should have divided the required frequency by the row total;.

     Hence, here we divide the  frequency of the female students who prefer playing sports i.e. 18 by the row total i.e. 53 ; we obtain:

18/53-0.3396

which is approximately equal to 34%.

Hence, option: D is correct.

5 0
3 years ago
Read 2 more answers
Help please and thank you
katrin2010 [14]
-3(-4y+3)+7y12y-9+7y19y-9The answer is A
3 0
3 years ago
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