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2 years ago

Help i am stuck 48/r = 12

2 answers:

5 0

R=4 It would be this because you have to solve the rational equation by combining expressions and isolating the variable r.

DiKsa [7]2 years ago

4 0

Answer:48/12 is how you solve this so your answer is 4 BRAINLY PLZZZZZZZZZZ

Step-by-step explanation:

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Find the value of x

AveGali [126]

Answer:

x = 120

Step-by-step explanation:

Since they are supplementary, they add up to 180 degrees.

So, you can say x + x/2 = 180

Then, you would solve it like an algebra problem.

Multiply both sides by 2

2x + x = 360

Simplify

3x = 360

Divide both sides by 3

x = 120

8 0

1 year ago

Given: N is the midpoint of LQ,

nlexa [21]

Answer:

6. SAS Postulate

5. ASA Postulate

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Given point B is located at

ELEN [110]

Answer: $\Large\boxed{Point~B'~=~(-4,~-2)}$

Step-by-step explanation:

Given information

Point B = (-2, -4)

Reflection line: y = x

Concept:

When reflecting over the line y = x, the position of y and x in the original coordinate switches places.

This is because it is " y = x ", assuming that they could interchange

Find the coordinate of Point B'

Original (x, y) = (-2, -4)

Point B' = (x', y') = (y, x) = $\Large\boxed{(-4,~-2)}$

Please refer to the attachment below for a graphical understanding

Hope this helps!! :)

Please let me know if you have any questions

4 0

9 months ago

Help, I don’t understand this DeltaMath question

djyliett [7]

I can use the angle and the length of JH to find the length of IJ.

To do this, I look at the relationship IJ and JH have to the 52 degree angle. JH is opposite to angle I, and IJ is adjacent to angle I. Because the two side lengths are opposite and adjacent, I use the tangent function to solve this.

Tangent of an angle = the length of the opposite side / the length of the adjacent side. This is just another way to say tan(x)=opposite/adjacent

Now I can fill in what I know...
tan(52)=4.2/x
Now, I want to isolate x.
tan(52) = 4.2/x
x(tan(52))=4.2
x=4.2/tan(52)

Now I put 4.2/tan(52) into a calculator and get x = 3.3 ft

Hope this helps!

7 0

2 years ago

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

2 years ago