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umka21 [38]
3 years ago
9

Suppose h(t) = -0.2t? + 2t models the height, in feet, of a ball that is kicked into the air where t is

Mathematics
1 answer:
ipn [44]3 years ago
7 0

Answer:

Below in BOLD.

Step-by-step explanation:

h(t) = -0.2t^2 + 2t

We can find the maximum height and the time by converting to vertex form:

h(t) = -0.2(t^2 - 2t)

= -0.2[(t - 1)^2 - 1)

= -0.2(t - 1)^2 + 0.2

The time to get to maximum height = 1 second and the maximum height is 0.2 m.

When the ball reaches the ground h = 0 so

-0.2(t - 1)^2 + 0.2 = 0

(t - 1)^2 =  -0.2 / -0.2 = 1

t - 1 = 1

t = 2 seconds.

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Consider the graph of the line y = .5x- 4 and the point
Katena32 [7]

Answer:

slope of parallel line and perpendicular line are 5 and -1/5 espectively

equation of parallel and perpendicular line are y = 5x + 22 y= \frac{-1}{5} x+\frac{6}{5} respectively

Step-by-step explanation:

y = 5x - 4 is in the form

y = mx + c

where m is the slope of the line and c is the y intercept of thr line

therefore slope of the line = 5 and y intercept = -4

when an another line is parallel to the given line then the slope of both the lines are equal

therefore the slope the parallel line = 5

equation of a line passing through a given point (x_{1} ,y_{1}) with slope m is given by y-y_{1} = m(x-x_{1} )

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therefore equation of line y-2 = 5(x+4)

therefore y = 2+ 5x+20

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when two lines are perpendiculer then

m_{1} m_{2}=-1

where m_{1} and m_{2} are slope of the lines therefore

m×5=-1

therefore m= \frac{-1}{5}

therefore eqaution of line passing through (-4,2) and with slope m= \frac{-1}{5} is given by y - 2= \frac{-1}{5} (x+4)

y= \frac{-1}{5} x+\frac{6}{5}

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3 years ago
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