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Ivan
1 year ago
9

The ratio of students who play musical instruments to students who play sports is 3:20. if there are 40 students who play sports

, how many students play musical instruments?
Mathematics
1 answer:
melomori [17]1 year ago
8 0

Based on the ratio, 6 students play musical instruments.

The mentioned problem can be solved using the concept of ratio and proportion. We will equate the two ratio. Let us assume the number of students who play musical instruments be x.

Forming the equation -

3 : 20 = x : 40

Rewriting the equation with respect to x

x = (40 × 3) ÷ 20

Performing multiplication and division on Right Hand Side of the equation

x = 120 ÷ 20

Performing division on Right Hand Side of the equation

x = 6

Therefore, 6 students play musical instruments.

Learn more about ratio and proportion -

brainly.com/question/19994681

#SPJ4

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Find the moment of inertia about the y-axis of the thin semicirular region of constant density
arlik [135]

The moment of inertia about the y-axis of the thin semicircular region of constant density is given below.

\rm I_y = \dfrac{1}{8} \times \pi r^4

<h3>What is rotational inertia?</h3>

Any item that can be turned has rotational inertia as a quality. It's a scalar value that indicates how complex it is to adjust an object's rotational velocity around a certain axis.

Then the moment of inertia about the y-axis of the thin semicircular region of constant density will be

\rm I_x = \int y^2 dA\\\\I_y = \int x^2 dA

x = r cos θ

y = r sin θ

dA = r dr dθ

Then the moment of inertia about the x-axis will be

\rm I_x = \int _0^r \int _0^{\pi}  (r\sin \theta )^2  \ r \  dr \  d\theta\\\\\rm I_x = \int _0^r \int _0^{\pi}  r^3 \sin ^2\theta  \  dr \  d\theta

On integration, we have

\rm I_x = \dfrac{1}{8} \times \pi r^4

Then the moment of inertia about the y-axis will be

\rm I_y = \int _0^r \int _0^{\pi}  (r\cos\theta )^2  \ r \  dr \  d\theta\\\\\rm I_y = \int _0^r \int _0^{\pi}  r^3 \cos ^2\theta  \  dr \  d\theta

On integration, we have

\rm I_y = \dfrac{1}{8} \times \pi r^4

Then the moment of inertia about O will be

\rm I_o = I_x + I_y\\\\I_o = \dfrac{1}{8} \times \pi r^4 + \dfrac{1}{8} \times \pi r^4\\\\I_o = \dfrac{1}{4} \times \pi r^4

More about the rotational inertia link is given below.

brainly.com/question/22513079

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3 0
2 years ago
Stephen drew a right angle how many obtuse agles are there
Shalnov [3]
There are no obtuse angles
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4 years ago
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I have to find the value of x​
Debora [2.8K]

Answer:

x = 10

Step-by-step explanation:

To find x, write a proportion between the side lengths for the similar triangles in the figure.

\frac{x+5}{x}=\frac{18}{12}

To solve, cross multiply and isolate x.

(x+5)(12) = 18(x)

12x + 60 = 18x

60 = 6x

10 = x

4 0
3 years ago
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