Question

2. A ball is thrown into the air with an initial upward velocity of 48 ft/s. It height h in feet after t seconds is given by the function h (t) = – 16t² + 48t + 4.
i.) What height will the ball be when 2 seconds has passed?


ii.) In how many seconds will the ball reach its maximum height?


iii.) What is the ball’s maximum height?

Answer 1

The first answer is the right one sjskememdlgsyendx