Let's just make 15 students a group. how many groups are there if there r 135 student? 135/15 = 9 groups.
so if each group have 4 adults just multiply 9 by 4,
therefore there will be 36.adults.
Okay, so I really hope that you can read all my work. I just spent the last 45 mins doing this problem as neatly as possible with as much detail as possible. So, I really hope my work doesn't confuse you.
My Final Answers were:
JI= 40 units (found using the Pythagorean theorem)
IM= 66.66 units = 66 and 2/3rds (found by dividing the length of JL by the cosine of ∠JIM )
LM=42.66 units = 42 and 2/3rds (found by IM= 24+LM; solve for LM since we know IM=66.66)
JM= 53.33 units= 53 and (1/3rd) (found by using the Pythagorean theorem; this time using JI as "a" and IM as c)
Hope this helped and all made sense!
(Pythagorean theorem is a²+b²=c²)
Answer:
I think that it would be D
Step-by-step explanation:
The two equations are vertical angles, which mean they are equal.
Set each equation to equal each other and solve for x.
3x-3 = 6(x-10)
Simplify the right side:
3x-3 = 6x-60
Subtract 3x from each side:
-3 = 3x - 60
Add 60 to each side:
57 = 3x
Divide both sides by 3:
x = 57 / 3
x = 19
4.67= 4 67/100
67 is a prime number, so the only fraction 67 hundredths can be represented by is 67/100.