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3 years ago

Complete the work to simplify the expression (-2d^5)^4

Mathematics

2 answers:

Fiesta28 [93]3 years ago

4 0

16d^20

Apply the product rule to rule to -2d^5.

Raise -2 to the power of power of 4.

16(d^5)^4

Multiply the exponents in (d^5)^4

etc...

klio [65]3 years ago

3 0

Answer:

16d^20

Step-by-step explanation:

to raise a product to a power, raise each factor to that power. (-2)^4x(d^5)^4

evaluate the power (-2)^4 x (d^5)^4

16 x (d^5)^4

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iris [78.8K]

The equilibrium price is $1.12.
If price is $0.98, there would be scarcity of Super Widgets.
When price is $0.98, quantity demanded is y.
When price is $0.98, quantity supplied is x.
When price is $1.22, there would be a surplus of Super Widgets.

<h3>What is equilibrium? </h3>

Equilibrium price is the price at which the quantity demanded equals the quantity supplied. The equilibrium price is $1.12.

Above equilibrium price, quantity supplied would exceed quantity demanded and there would be a surplus. When price is below equilibrium price, quantity supplied would be less quantity demanded and there would be a scarcity.

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2 years ago

Is the expression 3x+2 a binomial?

Wewaii [24]

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3 years ago

A candy company can make 360 pounds of chocolate in 6 hours how much can they make in 10 hours

LiRa [457]

Answer:

600

Step-by-step explanation:

divide 360 by 6 and you get how many pounds that can make in one hour.

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3 years ago

Kayla is having a neighbor watch her dog while she is gone for the week she decides to take 7/8 of a pound of dog food and put i

777dan777 [17]

Answer:

1/ 8 pounds of dog food

Step-by-step explanation:

Given that:

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(7/8) ÷ 7

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4 0

3 years ago

The exponential decay graph shows the expected depreciation for a new boat, sell g for $3500, over 10 years.

Alisiya [41]

Okay, the exponential function is
$g = a^{x}$
The start price of it in t=0 is 3,500, as we can see on the graph. Then, the function becomes
$g = 3500^{x}$
Let's see at t=2, where the price is g=2000:
$2000 = 3500^{x}$
Take natural logarithm:
$ln 2000 = ln 3500^{x}$
$x*ln 3500 = ln 2000$
$x = \frac{ln 2000}{ln 3500} = 0.93$
So, the difference between t=0 and t=2 is
$x_{t=0} - x_{t=2} = 1 - 0.93 = 0.07$
And then we get the change of x in one year equal to 0.035.
So, the final equation is
$g = 3500^{1-0.035t}$
You can insert any t and see that it is correct, for example t=7

8 0

3 years ago