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Gelneren [198K]
3 years ago
8

Seven hundred twelve thousandths in standard form and expanded form ​

Mathematics
1 answer:
pav-90 [236]3 years ago
7 0

Answer:

Standard: 0.712

Expanded: 0.7 + 0.01 + 0.002

Step-by-step explanation:

Seven hundred twelve thousandths

.tenths,hundredths,thousandths

0.712

Every number in expanded fits in its place.

0.712

^          ^         ^

0.7     0.01     0.002

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An object, which is at the origin at time t=0, has initial velocity V0= (-14.0i - 7.0j)m/s and constant acceleration a=(6.0i + 3
sesenic [268]
I am pretty sure the first thing we should do is to <span>integrate acceleration into velocity
And we will have: </span>a(t) = \ \textless \ 6,3\ \textgreater \v(t) = \ \textless \ (6t+C),(3t+C)\ \textgreater \ ; where    -- v(0) = \ \textless \ -14,-7\ \textgreater \
Then calculate v :&#10;v(t) = \ \textless \ (6t-14),(3t-7)\ \textgreater \
As you can see, velocity is zero and none of the objects is moving. It happens when <span> t=7/3 which means we can calculate this in the way we did (integrating) :
</span>p(t) = \ \textless \  (3t^2-14t+C) , ((3/2)t^2-7t+C) \ \textgreater \ &#10;
The product is <span>p(0) = 0 that makes us to reduce vector function to</span>p(t) = \ \textless \  (3t^2-14t) , ((3/2)t^2-7t) \ \textgreater \   where t = 7/3p(7/3) = \ \textless \  -49/3 , -49/6 \ \textgreater \<span>

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4 years ago
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Can any one solve this please....I kinda need this​
FrozenT [24]

9514 1404 393

Answer:

  • t₂ = 2
  • t₃ = 2

Step-by-step explanation:

The given expression says ...

  t_n+1=3\\\\t_n=2\qquad\text{for any value of n}\\\\t_2=2\\\\t_3=2

8 0
3 years ago
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Whats the square root of 10?? For each to the nearest 0.05.​
Vesnalui [34]

Answer:

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Step-by-step explanation:

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3 years ago
Suppose that the amount of time T a customer spends in a bank is exponentially distributed with an average of 10 minutes. What i
Bad White [126]

Answer:

The probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is 0.6065.

Step-by-step explanation:

The random variable <em>T</em> is defined as the amount of time a customer spends in a bank.

The random variable <em>T</em> is exponentially distributed.

The probability density function of a an exponential random variable is:

f(x)=\lambda e^{-\lambda x};\ x>0

The average time a customer spends in a bank is <em>β</em> = 10 minutes.

Then the parameter of the distribution is:

\lambda=\frac{1}{\beta}=\frac{1}{10}=0.10

An exponential distribution has a memory-less property, i.e the future probabilities are not affected by any past data.

That is, <em>P</em> (<em>X</em> > <em>s</em> + <em>x</em> | <em>X</em> ><em> s</em>) = <em>P</em> (<em>X</em> > <em>x</em>)

So the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is:

P (X > 15 | X > 10) = P (X > 5)

\int\limits^{\infty}_{5} {f(x)} \, dx =\int\limits^{\infty}_{5}  {\lambda e^{-\lambda x}} \, dx\\=\int\limits^{\infty}_{5}  {0.10 e^{-0.10 x}} \, dx\\=0.10\int\limits^{\infty}_{5}  {e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10}|^{\infty}_{5}\\=[-e^{-0.10 \times \infty}+e^{-0.10 \times 5}]\\=0.6065

Thus, the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is 0.6065.

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Its c because i did it already and got it right
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