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2 years ago

MATH Simplify the expression -6w + (-8) + 1 + (-7w)

Mathematics

1 answer:

Luba_88 [7]2 years ago

3 0

Answer: -13w - 7

Step-by-step explanation:

-6w + (-8) + 1 + (-7w)

Combine the like terms

-8 + 1 = -7

-6w + (-7) + (-7w)

-6w + (-7w) = -13w

-13w + (-7)

However, because adding a negative number is the same as subtracting the number as a positive, you can just make it -13w - 7

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\large -6x+6y=6<br> \large 6x+3y=12

Kaylis [27]

Answer:

the solution of the system is:

x = 1 and y = 2.

Step-by-step explanation:

I suppose that we want to solve the equation:

-6*x + 6*y = 6

6*x + 3*y = 12

To solve this, we first need to isolate one of the variables in one of the equations.

Let's isolate y in the first equation:

6*y = 6 + 6*x

y = (6 + 6*x)/6

y = 6/6 + (6*x)/6

y = 1 + x

Now we can replace this in the other equation:

6*x + 3*(1 + x) = 12

6*x + 3 + 3*x = 12

9*x + 3 = 12

9*x = 12 - 3 = 9

x = 9/9 = 1

Now that we know that x = 1, we can replace this in the equation "y = 1 + x" to find the value of y.

y = 1 + (1) = 2

Then the solution of the system is:

x = 1 and y = 2.

6 0

2 years ago

An investment broker puts 1/12 of his paycheck into a retirement account every quarter? How much of his $84,000 salary is put in

posledela

Answer:

<u>$7000</u> of his salary is put into this account each quarter.

Step-by-step explanation:

Given:

An investment broker puts 1/12 of his paycheck into a retirement account every quarter.

His salary is $84,000.

Now, to find how much is put into this account each quarter.

As given salary = $84,000.

So, amount to put into this account every quarter =

$\frac{1}{12} of\ \$84,000.$

$=\frac{1}{12} \times 84000$

$=\frac{84000}{12}$

$=\$7000.$

Therefore, $7000 of his salary is put into this account each quarter.

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2 years ago

Can someone please help me with numbers 1, a, b, c, 2, a, b, c

algol [13]

Thank you thank you very much

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2 years ago

Half of a set of the parts are manufactured by machine A and half by machine B. Ten percent of all the parts are defective. Six

baherus [9]

Answer:

The probability that a part was manufactured on machine A is 0.3

Step-by-step explanation:

Consider the provided information.

It is given that Half of a set of parts are manufactured by machine A and half by machine B.

P(A)=0.5

Let d represents the probability that part is defective.

Ten percent of all the parts are defective.

P(d) = 0.10

Six percent of the parts manufactured on machine A are defective.

P(d|A)=0.06

Now we need to find the probability that a part was manufactured on machine A, and given that the part is defective :

$P(A|d) =\frac{P(A \cap d)}{P(d)}$

$P(A|d) =\frac{P(d|A)\times P(A)}{P(d)}\\P(A|d)= \frac{0.06\times 0.5}{0.10}$

$P(A|d)= 0.3$

Hence, the probability that a part was manufactured on machine A is 0.3

8 0

2 years ago

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 4 h, and Car B traveled the dista

Kamila [148]

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3 years ago