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AlladinOne [14]
2 years ago
11

MATH Simplify the expression -6w + (-8) + 1 + (-7w)

Mathematics
1 answer:
Luba_88 [7]2 years ago
3 0

Answer: -13w - 7

Step-by-step explanation:

-6w + (-8) + 1 + (-7w)

Combine the like terms

-8 + 1 = -7

-6w + (-7) + (-7w)

-6w + (-7w) = -13w

-13w + (-7)

However, because adding a negative number is the same as subtracting the number as a positive, you can just make it -13w - 7

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Answer:

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Step-by-step explanation:

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3 years ago
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If the measurment of the angles of a triangle are 3b,2b,and 4b then what is the smallest angle
d1i1m1o1n [39]

Given:

The measurement of the angles of a triangle are 3b,2b,and 4b.

To find:

The smallest angle.

Solution:

According to the angle sum property, the sum of all angles of a triangle is 180 degrees.

3b+2b+4b=180^{\circ}           [Angle sum property]

9b=180^{\circ}

Divide both sides by 9.

b=20^{\circ}

Now,

3b=3(20^{\circ})=60^{\circ}

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3 years ago
At a bargain store, Tanya bought 3 items that each cost the same amount. Tony bought 4 items that each cost the same amount, but
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3 0
3 years ago
A student answer 86 problems on a test correctly and received a grade of 98% how many problems were on the test if all the probl
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Answer:

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2 years ago
Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

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⇒ x + iy = \dfrac{15-2-13i}{9+4}

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Thus, the given complex number in standard form as "1 - i".

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3 years ago
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