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AVprozaik [17]
2 years ago
14

You are buying carpet to cover a room that measures 21 feet by 30 feet. The carpet

Mathematics
1 answer:
Elina [12.6K]2 years ago
4 0

Answer:

20.97

Step-by-step explanation:

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Uppose a triangle has a,b and c what must be true?
alexdok [17]
Obtuse: b^2 + c^2 > a^2

Right: b^2 + c^2 = a^2

Acute: b^2 + c^2 < a^2



A^2 + B^2 + c^2 - 2bc*cosA
As (A), is an Obtuse cos A is Negative say 2bccosA = - k then;
a^2 = b^2 + c^2 + k
a^2 > b^2 + c^2


So, your Answer would be (B)
Hope this helps!!.!

6 0
3 years ago
Read 2 more answers
Using the image, determine the length of each arc.<br> m RC=<br> m CBR =
Montano1993 [528]

<u>Given</u>:

Given that the measure of ∠CDR = 85°

We need to determine the measure of \widehat{RC} and \widehat{CBR}

<u>Measure of arc RC:</u>

Since, we know that if a central angle is formed by two radii of the circle then the central angle is equal to the intercepted arc.

Thus, we have;

m\angle CDR = m \widehat{RC}

Substituting the values, we get;

85^{\circ} = m \widehat{RC}

Thus, the measure of \widehat{RC} is 85°

<u>Measure of arc CBR:</u>

We know that 360° forms a full circle and to determine the measure of arc CBR, let us subtract the values 360 and 85.

Thus, we have;

m\widehat{CBR}=360^{\circ}-m \widehat{RC}

Substituting the values, we have;

m\widehat{CBR}=360^{\circ}-85^{\circ}

m\widehat{CBR}=275^{\circ}

Thus, the measure of \widehat{CBR} is 275°

6 0
3 years ago
5 divide 15x 15squared
Goryan [66]

Answer:

75

Step-by-step explanation:

(5 /15) x (15 squared = 75

4 0
2 years ago
Don't get this
kap26 [50]
I'll talk you through it so you can see why it's true, and then
you can set up the 2-column proof on your own:

Look at the two pointy triangles, hanging down like moth-wings
on each side of 'OC'.

-- Their long sides are equal,  OA = OB, because both of those lines
are radii of the big circle.

-- Their short sides are equal, OC = OC, because they're both the same line.

-- The angle between their long side and short side ... the two angles up at 'O',
are equal, because OC is the bisector of the whole angle there.

-- So now you have what I think you call 'SAS' ... two sides and the included angle of one triangle equal to two sides and the included angle of another triangle.
(When I was in high school geometry, this was not called 'SAS' ... the alphabet
did not extend as far as 'S' yet, and we had to call this congruence theorem
"broken arrow".)

These triangles are not congruent the way they are now, because one is
the mirror image of the other one.  But if you folded the paper along 'OC',
or if you cut one triangle out and turn it over, it would exactly lie on top of
the other one, and they would be congruent.

So their angles at 'A' and at 'B' are also equal ... those are the angles that
you need to prove equal.
5 0
3 years ago
.................................
Degger [83]

Answer: what ???? lol

3 0
3 years ago
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