Sorry I am late but the I think it is this, I don’t know the answer but here is what I know. answer is: Imagine a rectangle that has one vertex at the origin and the opposite vertex is A. Now that you can see the image of A(3,4) under the rotation is A’(-4,3). It is easier to rotate the points that lie on the axes, and these help us find the image of A.
POINT: (3,0) (0,4) (3,4)
IMAGE (3,0) (-4,0) (-4,3)
2x + 3 = 9 Move all terms not containing x to the right side of the equation.
2x = 6 Divide each term by 2 and simplify.
x=3
Option D:
is the solution
Explanation:
The given expression is 
We need to determine the solution of the expression.
<u>Solution:</u>
The solution of the expression can be determined by solving the expression for the variable x.
Thus, we have,

Adding both sides of the expression by 1, we get,

Dividing both sides of the expression by 3, we get,

Thus, the solution of the expression is 
Hence, Option D is the correct answer.
Answer:
Step-by-step explanation:
It is convenient to memorize the trig functions of the "special angles" of 30°, 45°, 60°, as well as the way the signs of trig functions change in the different quadrants. Realizing that the (x, y) coordinates on the unit circle correspond to (cos(θ), sin(θ)) can make it somewhat easier.
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<h3>20.</h3>
You have memorized that cos(x) = (√3)/2 is true for x = 30°. That is the reference angle for the 2nd-quadrant angle 180° -30° = 150°, and for the 3rd-quadrant angle 180° +30° = 210°.
Cos(x) is negative in the 2nd and 3rd quadrants, so the angles you're looking for are
150° and 210°
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<h3>Bonus</h3>
You have memorized that sin(π/4) = √2/2, and that cos(3π/4) = -√2/2. The sum of these values is ...
√2/2 + (-√2/2) = 0
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<em>Additional comments</em>
Your calculator can help you with both of these problems.
The coordinates given on the attached unit circle chart are (cos(θ), sin(θ)).
Answer:
A and B are parallel to D and C
or
A and D to B and C
basically do a line and expand them if they touch they are not parralelogram but if they don't they are