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zhenek [66]
3 years ago
11

What is the average rate of change of g over the interval [-2,4]

Mathematics
1 answer:
SashulF [63]3 years ago
4 0

Answer:

<h2>3</h2>

Average = sum of all the observations

Total number of observations

Average = 2+4

2

Average = - 6

2

3

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A marketing study was conducted to compare the mean age of male and femlae purchasers of a certain product. random and independe
notka56 [123]

Answer:

A. t ≥ 1.734

Step-by-step explanation:

Data given and notation  

\bar X_{m}=39.80 represent the mean for the sample male

\bar X_{f}=50.30 represent the mean for the sample female

s_{m}=10.040 represent the sample standard deviation for the males  

s_{f}=13.215 represent the sample standard deviation for the females  

n_{m}=10 sample size for the group male  

n_{f}=10 sample size for the group female  

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for females is higher than the mean for males, the system of hypothesis would be:  

Null hypothesis:\mu_{f}-\mu_{m}\leq 0  

Alternative hypothesis:\mu_{f} - \mu_{m}> 0  

We don't have the population standard deviation, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{f}-\bar X_{m})-\Delta}{\sqrt{\frac{s^2_{f}}{n_{f}}+\frac{\sigma^2_{m}}{n_{m}}}} (1)

And the degrees of freedom are given by df=n_m +n_f -2=10+10-2=18  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

What is the test statistic?

With the info given we can replace in formula (1) like this:  

t=\frac{(50.3-39.80)-0}{\sqrt{\frac{13.215^2}{10}+\frac{10.040^2}{16}}}}=2.001

Critical value

For this case since we have a right tailed test we need to look into the t distribution with 18 degrees of freedom a value that accumulates 0.05 of the area on the right, and on this case:

t_{crit}=1.734

And the rejection zone of the null hypothesis would be: A. t ≥ 1.734

For our case our calculated value is higher than the critical value so we have enough evidence to reject the null hypothesis at the 5% of significance.

8 0
4 years ago
The median for the given set of six ordered data values is 30.5.
nikdorinn [45]

Answer:

x = 15

The median is the middle number, however, in this case there are two:

25 and x

The formula is:

23 + x/2 = 30.5

Subtract 23 from both sides:

23 + x - 23 = 30.5 - 23

Simplify:

x/2 = 7.5

Multiply both sides by 2:

2x/2 = 7.5 ⋅ 2

Therefore:

x = 15

4 0
4 years ago
A train on a straight track goes in the positive direction for 6.7 km , and then backs up for 4.0 km . Is the distance covered b
RSB [31]

Answer:

Distance is greater than the displacement.

Step-by-step explanation:

We are given that a train on a straight track goes in the positive direction.

We have to find that distance covered by the train is greater than, lees than or equal to its displacement.

Train covered distance in positive direction=6.7 km

Train covered distance in back=4.0 km

Distance covered by the train=6.7+4=10.7 Km

Because distance is the length of path covered by object.

Displacement =Final position -Initial position

Displacement =6.7-4=2.7 km

        10.7 > 2.7

Distance > Displacement

Hence, Distance is greater than the displacement.

7 0
3 years ago
Help plz:))) I’ll mark u brainliest <br> ASAP!!!
iVinArrow [24]
What do you need help with?
3 0
3 years ago
If on the unit circle C, the distance from P(1, 0) to the point T ( 4/5 , 3/5 ) is x, determine the coordinates of the point at
AveGali [126]

Answer:

(\frac{4}{5}, -\frac{3}{5}  )

Step-by-step explanation:

The point P(1,0) and T(\frac{4}{5}, \frac{3}{5}  ) are on the unit circle C and the arc length from P to T is x.

Let us assume that point P - x i.e. the point obtained by moving clock wise direction along the circle from P is T'.

Because of the symmetry of the circle about the coordinate axes, the x-coordinate of point T' will be \frac{4}{5} and the y-coordinate will be -\frac{3}{5}.

So, coordinates of T' are (\frac{4}{5}, -\frac{3}{5}  ).

Here we must notice that point T' is the reflection point of T with respect to X-axis. (Answer)

3 0
3 years ago
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