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zhenek [66]
2 years ago
11

What is the average rate of change of g over the interval [-2,4]

Mathematics
1 answer:
SashulF [63]2 years ago
4 0

Answer:

<h2>3</h2>

Average = sum of all the observations

Total number of observations

Average = 2+4

2

Average = - 6

2

3

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What is the value of x in the diagram below? 2 right triangles are stacked. The bottom triangle has a side length of 9 units and
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Answer:

18 sqrt2/ sqrt3

Step-by-step explanation:

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Iif jessica ate 7 apples and liz ate 3 .how many fruits she hade left
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not enogh information how many did they start with... take the number of fruits they started with(lets just say the number of frits is :z) then take 7+3= 10

so youll need to

Z-10

Z= the number of fruits that was started with

hop this helps!

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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
Which expressions are equivalent to z + (z + 6)?
katrin2010 [14]

Answer:

z=3 because in the 2(z+3) is like (z+2)+(z+6)

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